Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴ 
≅ 736.2 to the nearest tenth foot
Answer:
<h2>4</h2>
Step-by-step explanation:
5k-2k=12
3k=12
k=4
I believe it’s B but i’m not too sure.
Answer:
Name a transversal - i
Name all corresponding angles -
6 = 8
1 = 3
2 = 4
5 = 7
Name all alternate exterior angles -
1 = 5
4 = 8
I’m sorry I can’t read that it’s too small..
