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miv72 [106K]
2 years ago
12

The perimeter of a rectangular garden is 296 m. If the width of the garden is 62 m, what is its length? PLEASE ANSWER ASAP.

Mathematics
2 answers:
True [87]2 years ago
8 0

Answer:

86 m

Step-by-step explanation:

Afina-wow [57]2 years ago
7 0
86m
perimeter is the sum of all 4 sides of a triangle.
62 is given as the width
62+62 = 124
124 is the sum of two sides
296-124 = 172
172 is the sum of the other two sides
you need to find 1 side so u divide 172 by 2
when you do that you end up with 86m
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Help help help help math math
omeli [17]
<h3>Answer:</h3>

5

<h3>Solution:</h3>
  • First, n*7 can be written as 7n.
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6 0
2 years ago
Read 2 more answers
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
1 year ago
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