Answer:
See answers below
Step-by-step explanation:
Perimeter of a square = 4L
L sis the side length of the square
L = 5x^4y^2
perimeter = 4(5x^4y^2)
perimeter = 20x^4y^2
2) Length = 6x-10
Width = 4x+3
Area of rectangle = Length * Width
Area of rectangle = (6x-10)(4x+3)
Area of rectangle = 24x^2+18x-40x-30
Area of rectangle= 24x^2-22x-30
perimeter = 2(L+W)
perimeter 2(6x-10+4x+3)
perimeter = 2(10x-7)
perimeter = 20x-14
Hence the perimeter of the rectangle is 20x-14
B = 3.
Plug it in to get -7 + 1 = -6
Yes they will all be trapezoid
g(x)=3x^2-2(x+7)/2x+5
g(-1)=3(-1)^2-2(-1)+7/2(-1)+5
Do the numerator first
(3)(-1)(-1)-2(-1)+7
3+2+7
=12
2(-1)+5
-2+5
=3
Numerator= 12 , Denominator=3
Numerator/ Denominator = 12/3=4
Answer: g(-1)=4
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
x=1+or- i square root of 22