The percentage by which the second increase of the item became 1.44 times more expensive is; 20%
<h3>Percentage Price Increase</h3>
Complete question is;
A store manager increased the price of an item twice by the same percent. By what percent was the second increase if the item became 1.44 times more expensive?
Let the price of the item be considered to be f(x).
Let p be the percent increase. Thus;
f(x) = xp²
We are told that at the second increase, the item became 1.44 times more expensive. Thus;
1.44x = xp²
1.44 = p²
p = √1.44
p = 1.2
Now, in percentage form, p = 120%
This means that the second increase was 20% more than the first.
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