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inysia [295]
2 years ago
10

A store manager increased the price of an item by the same percent twice.

SAT
1 answer:
gavmur [86]2 years ago
4 0

The percentage by which the second increase of the item became 1.44 times more expensive is; 20%

<h3>Percentage Price Increase</h3>

Complete question is;

A store manager increased the price of an item twice by the same percent. By what percent was the second increase if the item became 1.44 times more expensive?

Let the price of the item be considered to be f(x).

Let p be the percent increase. Thus;

f(x) = xp²

We are told that at the second increase, the item became 1.44 times more expensive. Thus;

1.44x = xp²

1.44 = p²

p = √1.44

p = 1.2

Now, in percentage form, p = 120%

This means that the second increase was 20% more than the first.

Read more about percentage price increase at; brainly.com/question/7828363

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The 2nd row has 15 + 3 = 18 chairs.

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where we use the formulas

\displaystyle \sum_{n=1}^N 1 = N

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