Answer:
a.
they did not co-evolve with the natural species and lack natural controls, like predators
Explanation:
For this we will use kinematic equations.
We need the time of flight to compute the range.
With the given information, the most useful formula is:
Δy=v0yt−g2t2
Because our equation is taking only vertical motion into account,
v0y=30sin(45)
Because we are looking for the range of the object,
Δy=0
This leaves us with only one unknown: t
0=30sin(45)t−g2t2
g2t2=30sin(45)t
g2t=30sin(45)
t=60gsin(45)
For horizontal distance, the formula we need is:
Δx=v0xt
Because we are taking into account the horizontal range,
v0x=30cos(45)
In substituting our derived values into the equation we can see that:
Δx=30cos(45)∗60gsin(45)
Range=30cos(45)∗60gsin(45)
The least weight of a bag in the top 5 percent of the distribution is; 246
From the complete question below, we are given;
Population mean; μ = 240
Population standard deviation; σ = 3
Z-score formula is;
z = (x' - μ)/σ
- Now, we want to find the least weight in the top 5 of the distribution and as such we will use;
1 - 0.05/2 = 0.025 as significance level
Z-score at significance level of 0.025 is 1.96
Thus;
1.96 = (x' - 240)/3
3 × 1.96 = x' - 240
x' = 240 + 5.88
x' = 245.88
Approximating to a whole number gives;
x' = 246
Complete question is;
A machine is used to fill bags with a popular brand of trail mix. The machine is calibrated so the distribution of the weights of the bags of trail mix is normal, with mean 240 grams and standard deviation 3 grams. Of the following, which is the least weight of a bag in the top 5 percent of the distribution?
Read more about z-score at; brainly.com/question/25638875
Act i believe so i hope this helps
