Question

 FIRST GETS BRAILIEST Michael finds that 35 customers at his grandfather's grocery store use a coupon. To simulate the behavior of the next 5 customers, he writes the numbers 1, 2, 3, 4, and 5 on cards and mixes them up. He writes down that 1, 2, and 3 represent someone using a coupon and 4 and 5 represent someone not using a coupon. Michael then randomly selects a card, puts it back, and records the number. He repeats this 5 times to represent 5 customers or 1 trial. He repeats this experiment for a total of 15 trials. The results are shown in the table. 43454 24511 55555 43453 55315 25215 32235 43311 11154 13342 42514 13223 44215 45313 13324 Using this simulation, what is the probability that, out of the next 5 customers, 4 or more will use a coupon? Enter your answer, as a fraction in simplified form, in the box. FIRST GETS BRAINLIEST

Answer 1

Answer:

$\frac{1}{3}$.

Step-by-step explanation:

We are given that,

1, 2, 3 represents someone using a coupon and 4, 5 represents someone not using a coupon.

Now, the results out of 15 trials of the experiment are given to be:

43454, 24511, 55555, 43453, 55315, 25215, 32235, 43311, 11154, 13342, 42514, 13223, 44215, 45313, 13324.

Since, we can see that, the only possibilities where 4 or more customers use coupons are:

32235, 43311, 13342, 13223 and 13324.

That is, out of 15 trials, there are total 5 trials in which 4 or more customers use coupons.

Thus, the probability of 4 or more customers using a coupon is $\frac{5}{15}$ = $\frac{1}{3}$.

Hence, the required probability is $\frac{1}{3}$.