Answer:
Answer: The similarities of linear model and interactive model is both of their sender carries the conversation. While the similarities of Linear and transactional is both of the message travels from sender to receiver. arrenhasyd and 161 more users found this answer helpful.
Explanation:
1. Dressmaking is the craft of sewing clothes and dresses .
2. Tailoring is the art of professionally designing , cutting , fitting , and finishing clothing .
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Based on the calculations, the solubility of PbCrO₄ in water at at 25°C is equal to 1.4 x 10⁻⁸ M.
<h3>How to calculate the solubility of PbSO₄?</h3>
The properly balanced chemical equation for the dissociation of PbSO₄ is given by:
PbCrO₄(s) ⇆ Pb²⁺(aq) + CrO₄²⁻(aq)
Initial 0 0
Change +x +x
Equib. conc. x x
<u>Note:</u> The Ksp of PbCrO₄ at 25°C is equal to 2.0 × 10⁻¹⁶.
Next, we would set up an equation from the ICE table for its Ksp;
Ksp = [Pb²⁺][CrO₄²⁻]
2.0 × 10⁻¹⁶ = [x][x]
2.0 × 10⁻¹⁶ = x²
x = √2.0 x 10⁻¹⁶
x = 1.4 x 10⁻⁸ M.
Read more on solubility here: brainly.com/question/15396081
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The mass of glucose solute dissolved in the solution is 6.739 Kg.
Recall that;
ΔT = K m i
ΔT = Freezing point depression
K =Freezing point depression constant = 1.86°C/mol
m = molality of the solution
i = Van't Hoff factor = 1 (molecular solution)
We have to find the freezing point depression from;
Freezing point depression = Freezing point of pure solvent - Freezing point of solution
Freezing point of pure water = 0°C
Freezing point of solution = -5. 8 ∘C
Freezing point depression = 0°C - (-5. 8 ∘C) = 5. 8 ∘C
Now;
m = ΔT/K i
m = 5. 8 ∘C/ 1.86°C/mol × 1
m = 3.12 m
But molality = number of moles of solute/mass of solvent in Kg
Molar mass of solute = 180 g/mol
Let the mass of solute be m
3.12 = m/180/12
3.12 = m/180 × 12
m = 3.12 × 180 × 12
m = 6739 g or 6.739 Kg
Learn more: brainly.com/question/6249935