Question

What would be the coordinates at 315° if the coordinates at 135° are at (-square root 2/2, square root 2/2)?

Answer 1

Answer:

We choose C

Step-by-step explanation:

the coordinates at 135° are at  ($\frac{-\sqrt{2} }{2}$, $\frac{\sqrt{2} }{2}$ )

As we can see, the x coordinate of the point is negative and the y coordinate of it is positive.

So this point is located at the quadrant ii

From  135 ° to 315°, it is rotated 180°

=> Each coordinate (x,y) is changed to (-x,-y)

= ($\frac{\sqrt{2} }{2}$, $-\frac{\sqrt{2} }{2}$ )  the new coordinate is located in quadrant iii

We choose C