Answer:
public static int factorial(int n) {
if (n >= 1 && n <=12) {
if (n==1)
return 1;
else
return n * factorial(n-1);
}
else
return -1;
}
Explanation:
Create a method called factorial that takes one parameter, n
Check if n is n is between 1 and 12. If it is between 1 and 12:
Check if it is 1. If it is 1, return 1. Otherwise, return n * function itself with parameter n-1.
If n is not between 1 and 12, return -1, indicating that the number is not in the required range.
For example:
n = 3 Is n==1, NO factorial(3) = n*factorial(2)
n = 2 Is n==1, NO factorial(2) = n*factorial(1)
n = 1 Is n==1, YES factorial(1) = 1.
Then factorial(2) = 2*1 = 2, factorial(3) = 3*2 = 6
Answer:
Follows are the explanation of the choices:
Explanation:
Following are the Pseudocode for selection sort:
for j = 0 to k-1 do:
SS = i
For l = i + 1 to k-1 do:
If X(l) < X(SS)
SS= l
End-If
End-For
T = X(j)
X(j) = X(SS)
X(SS) = T
End-For
Following are the description of Loop invariants:
The subarray A[1..j−1] includes the lowest of the j−1 components, ordered into a non-decreasing order, only at beginning of the iteration of its outer for loop.
A[min] is the least amount in subarray A[j.. l−1] only at beginning of the each loop-inner iterations.
Following are the explanation for third question:
Throughout the final step, two elements were left to evaluate their algorithm. Its smaller in A[k-1] would be placed as well as the larger in A[k]. One last is the large and medium component of its sequence because most and the last two components an outer loop invariant has been filtered by the previous version. When we do this n times, its end is a repetitive, one element-sorting phase.
Following is the description of choosing best-case and worst-case in run- time:
The body the if has never been activated whenever the best case time is the list is resolved. This number of transactions are especially in comparison also as a procedure, that will be (n-1)(((n+2)/2)+4).
A structure iterator at every point in the worst case that array is reversed, that doubles its sequence of iterations in the inner loop, that is:(n−1)(n+6) Since both of them take timeΘ(n2).
<span>The finished product is "output." In the electronic computer, data are the raw material or input to the computer.</span>
Answer:
The ethernet cable.
Explanation:
The connection to the switch or router might be disrupted with the disconnection of the cable. Ask the user to check if the ethernet cable is properly connected.
The Internet Engineering Task Force is the premier internet standard body that defines standard internet protocols like TCP/IP. It is a large community that consists of operators, network designers, researchers and vendors drawn from the internet society’s individual and organization bodies and is concerned with the evolution and the smooth operation of the internet.
