Differentiate 6+4x - x^2

Mathematics

1 answer:

vfiekz [6]2 years ago

3 0

Answer:

2x+4

Step-by-step explanation:

hope that helps

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Equation for the given function

Lera25 [3.4K]

Answer:

Step-by-step explanation:

hello :

g(x) = (x+2)(x-4)/(x+2)(x-1)

1 ) this function no exist for if : x= -2 and 1

so the denominater is : (x+2)(x-1)

so : b= 2 and c=1

2) the x- intercept is : 4

so the numerater is : (x+2)(x-4)

g(x) =0 if : (x+2)(x-4)=0

means x-4=0 ... ( x+2 ≠ 0)

note :

g(x) ≠ (x-4)/(x-1) except in the case x ≠ -2

7 0

3 years ago

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$