La respuesta es -4 porque es antes del 0
Answer:
Option A and
Step-by-step explanation:
we have
-----> equation A
This is the equation of a circle with center at the origin and radius units
-----> equation B
This is the equation of a line
we know that
The solution of the system of equations is the intersection point both graphs
using a graphing tool
The intersection points are and
see the attached figure
therefore
the x-coordinates of the solution are and
6 times 8 is 48
48 is the answerz
Answer:
a = √[(c — b)(c + b)]
Step-by-step explanation:
a^2 + b^2 = c^2
We can make "a" the subject by doing the following:
a^2+ b^2 = c^2
Subtract b^2 from both side:
a^2 = c^2 — b^2
Take the square root of both side
a = √(c^2 — b^2)
Since we have difference of two squares, we can simplify further as:
a = √[(c — b)(c + b)]
What triangle I don’t see one I just see a 32?