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zloy xaker [14]
3 years ago
6

I need some help plsssss

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

(6, - 5 )

Step-by-step explanation:

The parabola is symmetrical about x = 4

The point (2, - 5 ) is 2 units to the left of x = 4 ,then

the point 2 units to the right of x = 4 is (6, - 5 )

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The three inside angles (a,b and c) of a right-angled triangle are in the ratio 7:18:11
svet-max [94.6K]

Answer:

The three angles of the right-angled triangle are

a = 35°

b = 90°

c = 55°

Step-by-step explanation:

We are given the ratio of angles of a right-angled triangle

a:b:c = 7:18:11

Recall that the sum of interior angles in a right-angled triangle is always 180°

7x + 18x + 11x = 180

36x = 180

x = 180/36

x = 5

a:b:c = 7x:18x:11x

a:b:c = 7(5):18(5):11(5)

a:b:c = 35:90:55

a = 35°

b = 90°

c = 55°

Alternatively:

We are given that the smallest angle is 35°

a = 7x = 35

x = 35/7

x = 5

b = 18x

b = 18(5)

b = 90°

c = 11x

c = 11(5)

c = 55°

4 0
4 years ago
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One US dollar equals 0.84 euros. Margo wants to exchange $400 for euro. How many euros will she receive in exchange?
Evgen [1.6K]
400*0.84= 33.5 Euros
If Margo exchanges $1 at 0.84 euro then $400 would be 33.4 Euros
8 0
4 years ago
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Please solve this question based on integeration chapter
Olenka [21]

Answer:  -ln |cos x| - ln |sin x| + C

<u>Step-by-step explanation:</u>

.\quad \int\dfrac{sin^2x-cos^2x}{sin\ x\ cos\ x}dx\\\\\\=\int \dfrac{sin^2x}{sin\ x\ cos\ x}dx-\int \dfrac{cos^2x}{sin\ x\ cos\ x}dx\\\\\\=\int \dfrac{sin\ x}{cos\ x}dx-\int \dfrac{cos\ x}{sin\ x}dx\\\\\\=\int tan\ x\ dx - \int cot\ x\ dx\\\\=-ln |cos\ x|-ln|sin\ x| + C

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3 years ago
How many eighty-fours are in 672?
Vlad1618 [11]

Answer: 8

Step-by-step explanation:

We only need to take  672/84 = 8

So there are 8

If you can please give me a Brainliest, I only need 1 more to become an Ace, thank you!

3 0
2 years ago
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A 12 foot ladder is placed 4 feet away from a house as shown. What is the value of x, rounded to the nearest degree ?
Otrada [13]
This is a sohcahtoa question, in this case itd be cosine. The "cah" part stands for cos(x)=adjacent/hypotenuse. Using numbers it would be cos(x)=4/12. To find x youd have to take the cos^-1 of both sides so x=cos^-1(4/12)
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