The area of a rectangle is x2-2x-8. the width of the rectangle is (x+2) . what is the length?

Mathematics

1 answer:

bija089 [108]4 years ago

3 0

Assuming the first part of this is "x squared" then just factor the trinomial by inspection

You might be interested in

7k + 4 (1/4k - 6) = 8k + 3k + 12

erma4kov [3.2K]

Answer:

$7k + 4( \frac{1}{4} k - 6) = 8k + 3k + 12 \\ \\ 7k + k - 24 = 11k + 12 \\ 8k - 24 = 11k + 12 \\ - 3k = 36 \\ { \boxed{ \boxed{k = - 12}}}$

3 0

3 years ago

The heights, in inches, of the 11 basketball players on a

yarga [219]

ANSWER: 6 99

for height. inches. of the 11 basket

8 0

3 years ago

Read 2 more answers

А is 35% of B. then B А is 65:35.

Aleonysh [2.5K]

Find 35% of 65, since A= 35 and B= 65.

35%=.35

Multiply that by 65, for the percentage.

65*.35= 22.75

So, 35% of 65= 22.75

22.75 is not equal to 35.

This statement is false.

8 0

3 years ago

Read 2 more answers

Given tan of theta = -2 and pi/2; find cos(2theta)

Nata [24]

Given tan of theta = -2 and pi/2; find cos(2theta)
The identity of cos (2 theta)= $cos(2\theta )=\frac{1-tan^2\theta }{1+tan^2\theta }$
Given tan of theta = -2 and pi/2.
So, let's plug in tan theta= -2
$cos(2\theta)= \frac{1-(-2)^2}{1+(-2)^2}$
= $\frac{1-4}{1+4}$ (Squaring)
= $\frac{-3}{5}$ (simplifying)
So, cos ( 2 theta) = -3/5.
Now we can plug in tan theta = π/2
$cos(2\theta)= \frac{1-(π/2)^2}{1+(π/2)^2}$
= $\frac{1-pi^2/4}{1+pi^2/4}$ (Squaring)
= $\frac{4-pi^2}{4+pi^2}$ Simplifying
So, cos ( 2 theta)= -3/5 and (4-pi^2)/(4+pi^2)