Answer:
t = 2.5 s
Step-by-step explanation:
Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Its equation is :
The above equation is a quadratic equation. The general equation is :
Here, a = 16, b = 38.8 and c = 3
The solution of quadratic equation is given by :
So, at t = 2.5 s the balloon is in air.
First find the area of the parallelogram
Area of parallelogram = b x h
= 12 x 7
= 84
Then find area of kite
Area of kite = (xy)/2
= (7 x 12)/2
= 84/2
= 42
Now we are gonna subtract the area of the kite from the area of the parallelogram.
84 - 42 = 42
Therefore the area of the shaded region is 42.
Answer:
Ok is there options? Because that will make it easy but I dont think your supposed to ask for help on a district test