An equation of a line parallel to y=x-6, must have the same slope.
In this equation:
y=mx+b (slope-intercept form)
m is the slope:
The slope of the equation y=x-6 is m=1 (the number beside "x").
Now we have a point (-1,5) and the slope m=1.
Point-slope form of a line:
y-y₀=m(x-x₀)
so:
y-5=1(x+1)
answer: the equation of the line in point-slope form is :
y-5=1(x+1)
And the eqution of this line in slope-intercept form is:
y=x+6
y-5=(x+1)
y=x+1+5
y=x+6
Answer:
Step-by-step explanation:
Because you can't do -x+1 so it would be (1,0) and then you have x^2 +3x-4 which is (-5,6)
Answer is 10 and 170, complementary angles are 90°, while supplementary angles are 180 in total, if angle A is 80 then you subtract 90 by 80 and you get 10, so that is angle B, So then you are asked what is angle C. Which is part of the supplementary angle so you take the 10° that you got from B and then you subtract 180 by the 10, And thats how you get 170 and that's how you know that C is 170 (hope this explanation helps)
Answer:
y-2=1/3(x-3)
Step-by-step explanation:
Point slope formula: y-y1=m(x-x1)
m is slope.
y-2=1/3(x-3)
Hope this helps!
If not, I am sorry.
