The only way to have two numbers that are the same and add up to be 15
is if they're both 7.5 , but those don't multiply to be 36. So I guess there's
no answer that satisfies all the conditions of this question.
You do 2x20 which is basically 2x2 (4) add a zero and your answer is 40
A1 = 4
a2 = 5a1 = 5 x 4 = 20
a3 = 5a2 = 5 x 20 = 100
a4 = 5a3 = 5 x 100 = 500
a5 = 5a4 = 5 x 500 = 2,500
Tn = ar^(n-1); where a = 4, r = 5
Tn = 4(5)^(n-1) = 4/5 (5)^n
Explicit formular is Tn = 4/5 (5)^n
Recursive formular is
A system of linear inequalities in two variables consists of at least two linear inequalities in the same variables. The solution of a linear inequality is the ordered pair that is a solution to all inequalities in the system and the graph of the linear inequality is the graph of all solutions of the system.
Answer:
{1, 2, 3, 4, 5}
Step-by-step explanation:
Sample space is the set of all possible outcomes. Supposing that the 5 sided number cube has numbers one to five on its sides, the possible outcomes are the numbers that can be rolled, then its sample space is: {1, 2, 3, 4, 5}