The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
A plane that travels a distance , in kilometers, with a bearing of
sexagesimal degrees can be represented in standard position by means of the following expression:
(1)
We can obtain the resulting vector () by the principle of superposition:
(2)
If we know that ,
,
,
,
and
, then the resulting vector is:
The magnitude of the resultant is found by Pythagorean theorem:
And the bearing is determined by the following <em>inverse</em> trigonometric relationship:
(3)
If we know that and
, then the magnitude and the bearing of the resultant is:
The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
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