Question

In pea plants, round seeds are dominant to wrinkled seeds. If you cross two heterozygous plants, what would your ratios be for genotype and phenotype of the offspring?

Answer 1

Answer:

Genotype - RR - 25%, Rr - 50%, rr - 25% (1:2:1)

Phenotype - Round seeds - 75%, Wrinkled seeds - 25% (3:1)

Explanation:

Let the letter "r" stand for the alleles, where R is round seeds and r is wrinkled seeds. A genotype is an individual's genes represented through alleles. Phenotypes are how the genes express themselves. In other words, genotypes will be written using letters, the alleles, and phenotypes will be the possible outcomes of the alleles.

To find the ratios/percentages of the genotypes and phenotypes you can use a punnet squares. Both of the parent seeds have the genotypes Rr and the phenotype of round seeds.

If you create punnet square (which had four boxes in total) 1 will have RR, 2 will have Rr, and 1 will have rr. These are the ratios for the genotypes. Each box represents 25%, so the percentages will be 25, 50, and 25. Finally, 3 of these boxes (RR and Rr) will result in round seeds because those are domiant. Only the genotype rr will result in wrinkled phenotype. Therefore, the ratio is 3:1 or 75% to 25%.