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pochemuha
4 years ago
15

The Statistical Bulletin published by Metropolitan Life Insurance Co. reported that 2% of all American births result in twins. I

f a random sample of 8000 births is taken, find the mean, variance, and standard deviation of the number of births that would be result in twins.
Mathematics
1 answer:
morpeh [17]4 years ago
3 0

Answer:

Mean = 160 births

Variance = 156.8 births

Standard deviation = 12.522 births

Step-by-step explanation:

The mean number of births resulting in twins is given by the sample size (n=8000 births) multiplied by the probability of twins in any birth (p=2%).

M = 8,000*0.02=160\ births

In a binomial distribution like this one, the variance is given by:

V=n*p*(1-p)\\V = 8,000*0.02*(1-0.02)=156.8\ births

The standard deviation is simply the square root of the variance:

SD = \sqrt V=\sqrt156.8\\SD=12.522\ births

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2 cars c and d started to move to each other car c was 118 miles from Boston car d was 256 miles from Boston car c was going twi
Vadim26 [7]

Answer:

131.3 miles

Step-by-step explanation:

The two cars are moving from different directions. The total distance between the two cars = 118 miles + 256 miles = 374 miles.

Let us assume that the two cars meet at point O, let the distance between car c and O be d₁, the distance between car d and point O be d₂, hence:

d₁ + d₂ = 374 miles       (1)

Let speed of car d be x mph, therefore speed of car c = 2x mph (twice of car d). If it take the cars t hours to meet at the same point, hence

For car c:

2x = d₁/t

t = d₁ / 2x

For car d;

x = d₂/t

t = d₂/ x

Since it takes both cars the same time to meet at the same point, therefore:

d₁/2x = d₂ / x

d₁ = 2d₂

d₁ - 2d₂ = 0         (2)

Solving equation 1 and 2 simultaneously gives d₁ = 249.3 miles, d₂ = 124.7 miles

Therefore the distance from point of meet to Boston = 249.3 - 118 = 131.3 miles

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3 years ago
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5 0
3 years ago
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
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And a partridge in a pear tree. On the third day of Christmas,
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The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

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Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

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Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
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liubo4ka [24]

Answer:

B. 50%

Step-by-step explanation:

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Name one possible cross section of a sphere
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So, imagine cutting a ball in half.  What shape is left?  A circle!

Answer: circle
8 0
3 years ago
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