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elena-s [515]
3 years ago
15

Two jet planes simultaneously started travelling in opposite directions from the same airport. Four hours later they were 3800 m

iles apart. If one plane traveled 80 miles per hour faster than the other, what was the speed of each plane?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0
Represent the speed of the first plane by f and that of the second plane by s.
Then 4f+4s = 3800 miles, or f+s = 950 miles.  Thus, f + (f + 80) = 950, so that
2f = 870, and f = 435 mph.  Then s = (435+80)mph, or 515 mph.

The first plane flew at 435 mph and the second at 515 mph.

Check:  (4 hours)(435 mph) + (4 hours)(515 mph) = 3800 mi (as expected)
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