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olchik [2.2K]
3 years ago
10

No files or links please!

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0

Answer: there you go

Step-by-step explanation:

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Find the value of x.<br> 48<br> (7x + 13)<br> A. 7<br> B. 11<br> C. 3<br> D. 5
Lesechka [4]
The value of x is D. 5
3 0
3 years ago
A. y=1/2x-2 <br> b. y=-1/2x+3<br> c. y=2x+1<br> d. y= -2x+4
Lyrx [107]

d. y=-2x+4

this is because in the formula used y=mx+b, b is represented as the the "y" intersept, which is 4. the slope, which is -2, is represented as x in this formula. therefore, D. y=-2x+4 is the correct answer

7 0
3 years ago
Given the following functions f(x) and g(x), solve f[g(10)] and select the correct answer below: f(x) = 10x + 8 g(x) = x + 9 2,0
ikadub [295]
ANSWER
f(g(10)) = 198

EXPLANATION

The given functions are;

f(x) = 10x + 8
and

g(x) = x + 9


To find
f(g(10))
we need to find

f(g(x)) = f(x + 9)


f(g(x)) =10(x + 9) + 8



f(g(x)) =10x + 90 + 8


f(g(x)) =10x + 98



f(g(10)) = 10(10) + 98


f(g(10)) = 100 + 98


f(g(10)) = 198


The last option is the correct answer
7 0
3 years ago
Read 2 more answers
Which statement is true about Angle B P D? Line A B intersect line C D at point P. It is adjacent to Angle A P C. It is compleme
mel-nik [20]

Answer:

It is congruent to Angle A P C

Step-by-step explanation:

we know that

<u><em>Vertical angles</em></u> are the angles opposite each other when two lines cross. They are always congruent.

In this problem we have that

m\angle APC=m\angle BPC -----> by vertical angles

see the attached figure to better understand the problem

therefore

It is congruent to Angle A P C

7 0
3 years ago
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Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
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