The electric field inside a cell membrane is 8. 0 mn/c.

Graph the planet data, shown right, using the regression calculator. When you are done, click "resize window to fit data. " merc

raketka [301]

Answer: mercury and venus are (closer to) the sun than earth is. so their orbital periods are (shorter) than earths orbit. the further a planet is from the sun the (longer) it’s orbit is.

Explanation:

5 0

3 years ago

Read 2 more answers

Which one of these would have the strongest gravitational pull?

Rzqust [24]

Answer:

a large dance star

Explanation:

because it is bigger and heavier

6 0

3 years ago

Read 2 more answers

15. For a random sample of n = 64, find the probability of a sample mean being

mart [117]

Answer:

0.9726

Explanation:

The computation of the probability of a sample mean is shown below:

$P(\bar x < 24.3)$

To find the probability first we have to determine the z score which is

$z = \frac{\bar x - \mu_{\bar x}}{\sigma_{\bar x}} \\\\ = \frac{\bar x - \mu }{\frac{\sigma}{\sqrt{n} } } \\\\ = \frac{24.3 - 24}{\frac{1.25}{\sqrt{64} } }$

= 1.92

Now probability is

$P(\bar x < 24.3) \\\\= P(z < 1.92)$

= 0.9726

Hence, the probability of the sample mean is 0.9726

We simply applied the above formulas to determined the probability of a sample mean and the same is to be considered

6 0

3 years ago

Once you have your heap structure created, next you must use it as a backing structure to a priority queue. Develop a PriorityQu

saveliy_v [14]

Using the knowledge in computational language in python it is possible to write a code that Develop a PriorityQueue data structure in a file.

<h3>Writting the code in python:</h3>

import sys

class Node:

def __init__(self,key):

self.left = None

self.right = None

self.val = key

self.parent = None

class MinHeap:

def __init__(self, maxsize):

self.maxsize = maxsize

self.size = 0

self.Heap = Node(-1 * sys.maxsize )

self.FRONT = self.Heap

# A utility function to do inorder tree traversal

def isLeaf(self, node):

if node.left == None and node.right == Node:

return True

return False

# Function to swap two nodes of the heap

def swap(self, node1, node2):

node1.data, node2.data = node2.data, node1.data

# Function to heapify the node at pos

def minHeapify(self, node):

# If the node is a non-leaf node and greater

# than any of its child

if not self.isLeaf(node):

if (node.data > node.left.data or

node.data > node.right.data):

# Swap with the left child and heapify

# the left child

if node.left.data < node.right.data:

self.swap(node, node.left)

self.minHeapify(node.left)

# Swap with the right child and heapify

# the right child

else:

self.swap(node, node.right)

self.minHeapify(node.right)

# Function to insert a node into the heap

def insert(self, element):

if self.size >= self.maxsize :

return

self.size+= 1

self.bst_insert(FRONT, element)

current = FRONT

while current.parent != None and current.data < current.parent.data:

self.swap(current, current.parent)

current = current.parent

# Function to print the contents of the heap

def Print(self):

self.inorder()

# Function to build the min heap using

# the minHeapify function

def inorder(self, root):

if root:

inorder(root.left)

print(root.val)

inorder(root.right)

def bst_insert(self, root, node):

if root is None:

root = node

else:

root.next = node

self.FRONT = node

# Driver Code

if __name__ == "__main__":

r = Node(50)

bst_insert(r,Node(30))

bst_insert(r,Node(20))

bst_insert(r,Node(40))

bst_insert(r,Node(70))

bst_insert(r,Node(60))

bst_insert(r,Node(80))

# Print inoder traversal of the BST

inorder(r)

print('The minHeap is ')

minHeap = MinHeap(15)

minHeap.insert(5)

minHeap.insert(3)

minHeap.insert(17)

minHeap.insert(10)

minHeap.insert(84)

minHeap.insert(19)

minHeap.insert(6)

minHeap.insert(22)

minHeap.insert(9)

minHeap.minHeap()

minHeap.Print()

print("The Min val is " + str(minHeap.remove()))

See more about python at brainly.com/question/13437928

#SPJ1

6 0

2 years ago

What would the time be in delhi if the time in prime meridian is 10:00a.m

alukav5142 [94]

Answer:

Prime Meridian(Standard) =00:00am

India(Delhi)=+05:30am

Therefore the req time is 10:00+5:30

=3:30pm

8 0

3 years ago