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trasher [3.6K]
2 years ago
9

Choose all the numbers that are common multiples of 3 and 12.

Mathematics
1 answer:
spayn [35]2 years ago
6 0
<h3>Answers: 48 and 72</h3>

=========================================================

Explanation:

The number 12 is a multiple of 3 because 3*4 = 12.

So when looking for common multiples of 3 and 12, we simply need to look at multiples of 12.

The multiples of 12 are:

  • 12, 24, 36, 48, 60, 72, 84, 96, 120, ...

We see that 48 and 72 are on the list. The values 21, 27, 63, 81 are not on the list, so cross them out.

Now we could keep that list of multiples going to see if 844 is on there or not. A better method is to divide 844 over 12. If we get a whole number, then it's a multiple of 12.

844/12 = 70.333 approximately.

This shows that 844 is <u>not</u> a multiple of 12. So we cross 844 from the list.

Only 48 and 72 are multiples of 12 (and also multiples of 3).

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marishachu [46]

Answer:

1 and - 1

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope ( gradient ) )

y = x ← is in this form

with gradient m = 1

Parallel lines have equal gradients

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4 0
2 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
3 years ago
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