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2 years ago

Cross multiply to determine whether the fractions are equivalent.

Mathematics

1 answer:

cricket20 [7]2 years ago

5 0

Answer:

Solution

5/6=7/5

5×5=7×6

25=42

Your answer is 25=42.

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Let X be the number of purchases that Fred will make on the online site for a certain company (in some specified time period). S

Mrac [35]

Answer: ???

Step-by-step explanation:

6 0

3 years ago

Jacob is working two summer jobs, making $10 per hour washing cars and making $8 per hour landscaping. In a given week, he can w

Burka [1]

Answer:

Step-by-step explanation:

Let x represent the number of hours that that he spent washing cars.

Let y represent the number of hours that that he spent landscaping.

In a week, he can work no more than 19 total hours. This means that

x + y ≤ 19- - - - - - - - - - - -1

Jacob is working two summer jobs, making $10 per hour washing cars and making $8 per hour landscaping. He must earn at least $170. This means that

10x + 8y ≥ 170 - - - - - - - - - -2

If Jacob worked 4 hours landscaping, it means that

x + 4 ≤ 19

x ≤ 19 - 4

x ≤ 15

Also,

10x + 8 × 4 ≥ 170

10x + 32 ≥ 170

10x ≥ 170 - 32

10x ≥ 138

10x ≥ 138/10

x ≥ 13.8

The minimum number of hours is 14

6 0

3 years ago

Mr. James stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the groun

kozerog [31]

Answer:

42 m above the ground

Step-by-step explanation:

4 0

2 years ago

X and y are both bigger than 30. x and y have HCF 21 and LCM 1617. Find x and y.

Sunny_sXe [5.5K]

The values of x and y are 99 and 343

The HCF of numbers is the highest common factors of the numbers

The LCM of numbers is the lowest common multiple of the numbers

The HCF and the LCM are given as:

$HCF = 21$

$LCM = 1617$

Multiply the HCF and the LCM

$HCF \times LCM = 21 \times 1617$

$HCF \times LCM = 33957$

The product of the numbers x and y equals the product of the HCF and the LCM.

So, we have:

$x \times y = 33957$

<h3>Prime Factors</h3>

Express 33957 as a prime factor

$x \times y = 3^2 \times 7^3 \times 11$

Rewrite the equation as

$x \times y = 99 \times 7^3$

$x \times y = 99 \times 343$

By comparison:

$x = 99$

$y= 343$

Hence, the values of x and y are 99 and 343

Read more about HCF and LCM at:

brainly.com/question/420337

6 0

2 years ago

5x-(x+3)=1/3 (9x+18)-5<br> Please show me step by step

zzz [600]

Step-by-step explanation:

5x-(x+3)=1/3(9x+18)-5

5x-x+3=3x+6-5

1/3 multiplied by 9/1 is three because if you take away the ones and put your problem like this: 9/3, you'll get 3.

1/3 multiplied by 18/1 is six because if you take away the ones and switch to division, it'll look like this: 18/3. 18/3 is 6.

5x-1x+3=3x+6-5

If a variable is alone, you should - in this case - put a one before it, but if the variable is alone you should know that it's automatically a one.

4x+3=3x-1

6-5=1 Simple math problem, probably self explanatory

4x+3=3x-1

Subtract 3x from 4x and you'll get 1x because 4-3 is 1.

1x+3=-1

Then you add 3 to -1 which is 2.

The answer is 1x=2

Or you could've done:

4x+3=3x-1

-4x -4x

3=-1x-1

+-1 +-1

2=1x

It's the same answer, but all I did was subtract the 4x from the 4x and 3x.

3 0

2 years ago