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Svetllana [295]
2 years ago
14

The circle below has center 0, and its radius is 4 mm. Given that m ZAOB = 50°, find the length of the major arc ACB.

Mathematics
1 answer:
Mrrafil [7]2 years ago
8 0

\textit{arc's length}\\\\ s=\cfrac{r\theta \pi }{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{in~degrees}{angle}\\[-0.5em] \hrulefill\\ r=4\\ \theta =50 \end{cases}\implies s=\cfrac{(4)(50)\pi }{180}\implies s=\cfrac{10\pi }{9}~mm

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Write an equation if the line that is parallel to y=2x-5 and passes through (-4,2)
Leokris [45]

Answer:

Step-by-step explanation:

y=2x-5

From y=mx+c

Comparing the equation

M=2.

For parallelism

M₁=M₂

y-y₁=m(x-x₁) equation of a line passing through a point

point (-4,2) are x₁ and y₁ respectively

y-2=2(x-(-4))

y-2=2(x+4)

y-2=2x+8

y=2x+8+2

y=2x+10

5 0
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Pls help me with 4 and 5​
Arada [10]
4. 3x-27 = 90
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7 0
3 years ago
Can you use use the formula A = 1/2 x b x h to find the area of any triangle? Explain.
Morgarella [4.7K]
You can use it to find the area of a right triangle because a right triangle is basically a rectangle cut in half diagonally. However, this formula does not apply to all triangles because those that are not right triangles don't have a base or height, they're not really a rectangle. Because the formula for a rectangle's area is bxh, a right triangle is half of that. I hope this made sense and was helpful. :)
3 0
3 years ago
Read 2 more answers
I need help getting this please
insens350 [35]

Answer:

Step-by-step explanation:

f(x)=x²+2

a.

f(a)=a²+2+2=a²+4

b.

f(a+2)=(a+2)²+2=a²+4a+4+2=a²+4a+6

c.

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3 0
4 years ago
Find the limit, if it exists. (if an answer does not exist, enter dne.) lim (x, y) → (0, 0) x4 − 20y2 x2 + 10y2
Firdavs [7]
Traveling along the x-axis, we have

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{x\to0}\frac{x^4}{x^2}=\lim_{x\to0}x^2=0

On the other hand, along the y-axis we get

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{y\to0}\frac{-20y^2}{10y^2}=\lim_{y\to0}(-2)=-2

Therefore the limit doesn't exist.
5 0
3 years ago
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