Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value 
Depreciation rate is 
<h3>∴ r=0.045</h3>
Period , t=5 years
Substitute the values we get
∴ 
<h3>The value C(t) of the car after 5 years is $
12709</h3>
The equation would be 40+15p=70+5p. You would subtract 5p from each side (15-5) and (5-5) and you'll have 40+10p=70. You would then subtract 40 from each side (70-40) and (40-40) to have 10p=30. You would divide by both of the sides by 10, you would end up with p=3. P is price training. The reason you divide and subtract on both sides is because you want the months to be on one side and the price training on the other side.
Answer:
B
Step-by-step explanation:
all you need is to solve the first term
2x² - (-3x²) = 5x² ,
b is the only answer with 5x² in it
Answer:
About 4 times per year.
Step-by-step explanation:
Research studies online.
Two over four because you just multiply by two2/4
