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MArishka [77]
3 years ago
15

Determine which two sequences of transformation could be applied

Mathematics
1 answer:
algol133 years ago
8 0

Answer:

Step-by-step explanation:

yyygggggggggggggggggggggggg

nnnnnnnnnnnnnnnnn

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A recipe for bread uses 5 3/4 cups of white flour and 3 1/3 cups of wheat flour. How many more cups of white flour than wheat fl
natita [175]
The equation is just 5 3/4 times 3 1/3. You make the denominators the same by multiplying them by each other. It will be 5 3/12 times 3 1/12. Now you times these two together. You can do this part yourself because it will be confusing on here. I hope i helped atleast a little.
6 0
3 years ago
Which of these equations would give you the balance on an account with a principal of $3000 and an interest rate of 8%, compound
GrogVix [38]
It would be 3000 x 1.08^5
8 0
3 years ago
The ratio of the numerator and denominator of a rational number is 2 : 7 and
Nadya [2.5K]

Answer:

6/21.

Step-by-step explanation:

let the rational number be 2x/7x.

2x + 4 / 7x - 2 = 10 /19

Cross multiply:

19(2x + 4) = 10(7x - 2)

38x + 76 = 70x - 20

96 = 70x - 38x

32x = 96

x = 3.

So the rational number is  2*3/ 7*3

= 6/21.

4 0
3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
BRAINLIEST
kenny6666 [7]

Answer:

B. 1 1/3

Step-by-step explanation:

\frac{5}{6} + \frac{3}{6} = \frac{8}{6}

\frac{8}{6} = \frac{4}{3}

three can go into 4 once, so we have a whole number of 1 and a leftover 1/3.

= 1\frac{1}{3}

hope this helps :)

4 0
2 years ago
Read 2 more answers
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