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stealth61 [152]
4 years ago
5

There were 165 donors last year. Find the number of donors this year using each of the expressions. Do you get the same number w

ith each of the expressions?
Mathematics
1 answer:
pochemuha4 years ago
4 0

Answer:

We need to see the expressions given

Step-by-step explanation:

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Need help with my Geometry, can someone help me with 4,5 and 10?
xz_007 [3.2K]
For questions 4 and 5, use laws of complementary and supplementary angles to find values of x. I'm not too sure about what question 10 is asking.

Hope I helped :)

6 0
3 years ago
Read 2 more answers
A table with a round top is cut in half so that it can be used against a wall.after it is cut,the edge along the wall is 6 feet
MrRissso [65]

Answer:

The area of the table after it is cut is 12 or 36 because

Step-by-step explanation:

6 times 2= 12 and 6 times 6= 36 so year

4 0
3 years ago
Is 5 1/4 divided by 3 1/2 the same as 3 1/2 divided by 5 1/4?
sashaice [31]

Answer:

no it is not the same because you get different answers

4 0
3 years ago
kell works at an after-school program at an elementray school. on monday he work for 1.5 hours and recived 12.6 dollars, on tues
Rina8888 [55]

Answer:

Kell would make more money working 10 hours than Markio.

Step-by-step explanation:

To find how much Kell makes per hour, you have to divide how much he worked by how much he earned. So on Monday, Kell worked 1.5 hours and received 12.6 dollars. Divide 12.6/1.5 and you'll find you're answer.

Monday:   12.6/1.5=<u>8.4</u>

On Tuesday, the problem states that he worked 2.5 hours and received 21 dollars. Divide 21/2.5 and you'll find the answer.

Tuesday:     21/2.5= <u>8.4</u>

On Wednesday, the problem states that he worked 4 hours and received 33.60. Divide 33.60/4 and you'll get you're answer.

Wednesday:    33.60/4= <u>8.4</u>

So we can conclude that Kell makes $8.40 per hour.

Now the problem states, Markio gets paid 7 dollars per hour. To find the answer to the question, you have to multiply how much they make per hour times 10 hours.

Markio:  7x10=70

Kell:  8.4x10=84

So to answer the question, Kell would make more money working 10 hours.


Hope it helps!

3 0
3 years ago
Find sin(a)&amp;cos(B), tan(a)&amp;cot(B), and sec(a)&amp;csc(B).​
Reil [10]

Answer:

Part A) sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}

Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sin(\alpha)=cos(\beta)

Find the value of sin(\alpha) in the right triangle of the figure

sin(\alpha)=\frac{8}{14} ---> opposite side divided by the hypotenuse

simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132

x=\sqrt{132}\ units

simplify

x=2\sqrt{33}\ units

Find the value of tan(\alpha) in the right triangle of the figure

tan(\alpha)=\frac{8}{2\sqrt{33}} ---> opposite side divided by the adjacent side angle alpha

simplify

tan(\alpha)=\frac{4}{\sqrt{33}}

therefore

tan(\alpha)=\frac{4}{\sqrt{33}}

tan(\beta)=\frac{4}{\sqrt{33}}

Part C) Find sec(\alpha)\ and\ csc(\beta)

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sec(\alpha)=csc(\beta)

Find the value of sec(\alpha) in the right triangle of the figure

sec(\alpha)=\frac{1}{cos(\alpha)}

Find the value of cos(\alpha)

cos(\alpha)=\frac{2\sqrt{33}}{14} ---> adjacent side divided by the hypotenuse

simplify

cos(\alpha)=\frac{\sqrt{33}}{7}

therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

csc(\beta)=\frac{7}{\sqrt{33}}

6 0
3 years ago
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