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lubasha [3.4K]
3 years ago
15

Write an equation in slope-intercept form for the line with y-intercept −8 and slope 1/3

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

y=1/3x-8

Step-by-step explanation:

The slope intercept form of a line is y=mx+b

m stands for slope and b stands for y intercept

So ... simply put 1/3 in for m and -8 in for b

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(Linear or non linear )’<br><br><br> Will mark brainliest hurry
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Answer:

linear

Step-by-step explanation:

7 0
3 years ago
Please help me I need it ​
Kitty [74]

Answer:(x - 1)(7x + 12)

Step-by-step explanation:

Question: (6x² + 5x - 3) + (x² - 9)

⇒(6x² + 5x - 3) + (x² - 9)

⇒6x² + 5x - 3 + x² - 9

rearrange

⇒6x² + x² + 5x - 3 - 9

⇒7x² + 5x - 12

Middle term break

⇒7x² + 12x - 7x - 12

⇒x(7x + 12) - 1(7x + 12)

⇒(x - 1)(7x + 12) Answer

hope that helps...

3 0
3 years ago
Brianna deposited $680 into a savings account that pays a simple annual interest rate of 1.29%. How much interest will she earn
andrew11 [14]
Here's what I got.

<span>680 X 1.29/100 X 3 = $26.32

ANSWER is D) </span>
3 0
3 years ago
Read 2 more answers
For the function, find all critical numbers and then use the second-derivative test to determine whether the function has a rela
Serhud [2]

Answer:

relative maximum: x = 1

relative minimum: x = 7

Step-by-step explanation:

Critical points:

Values of x for which f'(x) = 0.

Second derivative test:

For a critical point, if f''(x) > 0, the critical point is a relative minimum.

Otherwise, if f''(x) < 0, the critical point is a relative maximum.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(x) = x^{3} - 12x^{2} + 21x - 8

Finding the critical points:

f'(x) = 3x^{2} - 24x + 21

3x^{2} - 24x + 21 = 0

Simplifying by 3

x^{2} - 8x + 7 = 0

So a = 1, b = -8, c = 7

\bigtriangleup = (-8)^{2} - 4*1*7 = 36

x_{1} = \frac{-(-8) + \sqrt{36}}{2} = 7

x_{2} = \frac{-(-8) - \sqrt{36}}{2} = 1

Second derivative test:

The critical points are x = 1 and x = 7.

The second derivative is:

f''(x) = 6x - 24

f''(1) = 6*1 - 24 = -18

Since f''(1) < 0, at x = 1 there is a relative maximum.

f''(7) = 6*7 - 24 = 18

Since f''(x) > 0, at x = 7 there is a relative minumum.

8 0
3 years ago
Sam drove 320 miles in 2.5 hours, how long will it take to drive 500 at the same rate (speed)?
marishachu [46]

Answer:

D = (55)(4.5)  

425 = 60 T  

200 = R (2.5)  

4.6 hours  

59 mph  

217 miles




Step-by-step explanation:


6 0
4 years ago
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