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Pepsi [2]
2 years ago
7

An airplane is preparing to land at an airport. It is 50400 feet above the ground and is descending at the rate of 3000 feet per

minute. At the same​ airport, another airplane is taking off and will ascend at the rate of 2600 feet per minute. When will the two airplanes be at the same altitude and what will that altitude​ be? Use pencil and paper. Use two other methods to solve the problem. Explain which methods are easier to use and which are more difficult to use for the situation.
Mathematics
1 answer:
Dovator [93]2 years ago
3 0

Answer:

let t = no of minutes when they are at the same altitude

:

52200 - 3300t = 2500t

52200 = 3300t + 2500t

52200 = 5800t

t = 52200/5800

t = 9 minutes they will be at the same altitude

:

The altitude:

9*2500 = 22500 ft

:

Check on other train

52200 - 9(3300) =

52200 - 29700 = 22500 ft

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Help me solve this question
Monica [59]

Answer:

if you scored a 83 on every test in a class your standard deviation would be 0. The point is that the bigger the standard deviation the more "variation" you will find in the raw numbers.... "D" (international equities) is the answer to this question...

it has the highest percent for the standard deviation, this it is the

MOST IN-COSISTENT

Step-by-step explanation:

6 0
3 years ago
Samantha has 54 beads. Amanda has twice as many beads as Samantha. They are making bracelets it takes 8 beads to make a bracelet
wlad13 [49]

Answer:

On combining the beads they can make 20 bracelets.

Step-by-step explanation:

The number of beads Samantha has  =  54 beads

Number of beads Amanda has = 2 x( Number of beads Samantha has)

=  2  x 54  =  108 beads

The total number of beads Amanda and Samantha has  

=   54 beads + 108 beads

= 162 beads

Number of beads required to make 1 bracelet  =  8 beads

Now, \textrm{The number of bracelets made}  = \frac{\textrm{Total number of beads they both have}}{\textrm{Beads required to make 1 bracelet}}

=\frac{162}{8}  = 20.25≈  20

or, the total number of bracelets they can make is 20.

Hence, on combining the beads they can make 20 bracelets .

8 0
3 years ago
Different measurements are expressed in different units. Choose the correct SI units for the following types of measurement.
pashok25 [27]

Answer:

m/s

m/s^2

N

Kgs

Step-by-step explanation:

oqr-tjch-gux

pls jøin gøøgle meeť my frįend

:(

5 0
3 years ago
Read 2 more answers
7 3/9 - 2 4/9 =<br>11 3/4 - 5 1/4 =​
jeka57 [31]

1.)

7 \frac{3}{9}  - 2 \frac{4}{9}  \\  =  \frac{66}{9}  -  \frac{22}{9}  \\  =  \frac{44}{9}  \\  = 4 \frac{8}{9}

2.)

11 \frac{3}{4}  - 5 \frac{1}{4}  \\  =  \frac{47}{4}  -  \frac{21}{4}  \\  =  \frac{26}{4}  \\  =  \frac{13}{2}  \\  = 6 \frac{1}{2}

<em>Hope it helps and is useful :)</em>

6 0
3 years ago
The inches of rainfall in the rainforest is represented by the function f(x) = 3(x-2)+ 4. What is the average rate of change bet
nata0808 [166]

Answer:

The average rate of change of rainfall in the rainforest between 2nd year and 6th year = <u>3 inches</u>

Step-by-step explanation:

Given function representing inches of rainfall:

f(x)=3(x-2)+4

To find the average rate of change between the 2nd year and the 6th year.

Solution:

The average rate of change between interval [a,b] is given as :

\frac{f(b)-f(a)}{b-a}

For the given function we need to find the average rate of change between 2nd year and 6th year. [2,6]

So, we have:

f(2)=3(2-2)+4=3(0)+4=4

f(6)=3(6-2)+4=3(4)+4=12+4=16

Thus, average rate of change will be:

\frac{f(6)-f(2)}{6-2}

⇒ \frac{16-4}{6-2}

⇒ \frac{12}{4}

⇒ 3

Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches

8 0
3 years ago
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