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Pepsi [2]
2 years ago
7

An airplane is preparing to land at an airport. It is 50400 feet above the ground and is descending at the rate of 3000 feet per

minute. At the same​ airport, another airplane is taking off and will ascend at the rate of 2600 feet per minute. When will the two airplanes be at the same altitude and what will that altitude​ be? Use pencil and paper. Use two other methods to solve the problem. Explain which methods are easier to use and which are more difficult to use for the situation.
Mathematics
1 answer:
Dovator [93]2 years ago
3 0

Answer:

let t = no of minutes when they are at the same altitude

:

52200 - 3300t = 2500t

52200 = 3300t + 2500t

52200 = 5800t

t = 52200/5800

t = 9 minutes they will be at the same altitude

:

The altitude:

9*2500 = 22500 ft

:

Check on other train

52200 - 9(3300) =

52200 - 29700 = 22500 ft

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3 0
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The selling price of a refrigerator, is $739.20. If the mark up is 20% of the dealers cost , what is the dealers cost of the ref
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Mark up percentages are used to increase the prices of items

The dealers cost of the refrigerator is $591.36

<h3>How to determine the dealer cost</h3>

Represent the dealer cost of the refrigerator with x.

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Read more about mark ups at:

brainly.com/question/19104371

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2 years ago
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8 0
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You want to find the volume inside the hemisphere x^2+y^2+z^2=4 (i.e. inside the sphere but above the plane z=0) and outside the cylinder x^2+y^2=1. Call this region R.

In cylindrical coordinates, we have

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_1^2\int_0^{\sqrt{4-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

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