All categories

2 years ago

HELP!!!! I need help

Mathematics

1 answer:

ahrayia [7]2 years ago

3 0

Answer:

1 Tenths = 10 Hundredths

10.74 - 10.60 = 0.14

0.14 = 14 hundredths

Thus, you need 10 ones, 6 tenths and 14 hundredths to make 10.74.

You might be interested in

P=-3w+9 tell me the steps I already have the steps

anastassius [24]

You're solving for w for I assume.

P= -3w+9, put -3w on the left side and P on the right side.
3w= -P+9, divide both sides by 3.
w= -P+9 over 3.
w= -P over 3 plus 9 over 3.
(Final Answer):
w= -p over 3 plus 3.

Hope this helps.

4 0

2 years ago

What is the measure of what is the measure of (either 50,90,95, or 115)

Anuta_ua [19.1K]

Answer:

65 & 115

Step-by-step explanation:

<EGF = (180 - 50) /2 = 65 degree

<CGF = 180 - 65 = 115 degree

5 0

3 years ago

Plzzzzzz help am stuck

Olenka [21]

#2 is (a) 11.9 degrees

#3 is (d) -9.4 degrees

8 0

3 years ago

CAN SOMEONE HELP ME WITH PATTERN 1

jeyben [28]

1- 6
2- 4
3- 2
And that’s all I can tell you? It’s decreasing so I don’t think 10 would have any stars unless if negative numbers are allowed

5 0

2 years ago

I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Given:

$m\angle Z = 138^{\circ}$

Note the following:

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

5 0

2 years ago