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s2008m [1.1K]
2 years ago
11

HELP!!!! I need help

Mathematics
1 answer:
ahrayia [7]2 years ago
3 0

Answer:

1 Tenths = 10 Hundredths

10.74 - 10.60 = 0.14

0.14 = 14 hundredths

Thus, you need 10 ones, 6 tenths and 14 hundredths to make 10.74.

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In this 3x3 square, you can use only numbers from 1-9, to make all the rows and columns equal to 15. Good luck to the person sol
bulgar [2K]

Answer:

Hello,

Step-by-step explanation:

The well-known magic square. (first apparition in China).

Here it the methode du Marquis de Liouville: (odd square:3,5,7,9,11,13,...)

We are going to put successively the number from 1 to n² (here n=3)

We imagine that the square is put on a sphere;

We begin in the middle of the last line where we put 1

ICI:

We move in direction SE of one case and put le next number

until we reach of multiple of n

After have reached a multiple of n, we move verticaly of one case

and we go to ICI until we reach n²

8 0
3 years ago
(Sin5A/sina)-(cos5A/cosA)=4cos2A
Sonja [21]
Is there any way you could explain this to me?
8 0
2 years ago
How to find matrics M
makkiz [27]

\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]

(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1

(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]

3 0
3 years ago
Yuto and Lian are at train stations 1,880 kilometers apart. Yuto boards a train heading east at an average speed of 220
Doss [256]

Answer:

1,000 km

Step-by-step explanation:

Assume that when two train pass each other, Lian has traveled x (km)

=> The time Lian has traveled when two trains pass each other is:

<em>Time = Distance/ Rate = x/ 250 (hour)</em>

As Lian and Yuto travelled from the two opposite train stations and the train stations are 1,880 km apart

=> When two train pass each other, Yuto has traveled 1,880 - x (km)

=> The time Yuto has traveled when two trains pass each other is:

<em>Time = Distance/ Rate = (1,880 - x)/220 (hour)</em>

As Lian and Yuto board at the same time, so that when two trains pass each other, the time both of them have traveled is equal

=> <em>x/ 250 = (1,880 - x)/220</em>

<em>=> 220x = 250 x (1,880 -x) </em>

<em>=> 220x = 470,000 - 250x</em>

<em>=> 470x = 470,000</em>

<em>=> x = 1,000</em>

<em />

<em>So that, </em>when two train pass each other, Lian has traveled x = 1,000 km

<em> </em>

6 0
3 years ago
Read 2 more answers
Hey! This is my first question! The equation is relatively simple but something makes me not understand it. Your help would be g
Law Incorporation [45]

Answer:101°

Step-by-step explanation:

79 + 101=180

7 0
3 years ago
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