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s344n2d4d5 [400]
3 years ago
8

9.20 Divide it by 100 and write the product in expanded form​

Mathematics
1 answer:
DedPeter [7]3 years ago
4 0
565666666765665657557 is the answer or maybe it’s 6 sorry if it’s wrong
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An index that is a standardized measure used in observing infants over time is approximately normal with a mean of 90 and a stan
weqwewe [10]

Answer:

The proportion of children that have an index of at least 110 is 0.0478.

Step-by-step explanation:

The given distribution has a mean of 90 and a standard deviation of 12.

Therefore mean, \mu = 90 and standard deviation, \sigma = 12.

It is given to find the proportion of children having an index of at least 110.

We can take the variable to be analysed to be x = 110.

Therefore we have to find p(x < 110), which is left tailed.

Using the formula for z which is p( Z < \frac{x - \mu}{\sigma}) we get p(Z < \frac{110 - 90}{12} = 1.67).

So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)

Using the Z - table we can calculate p(Z < 1.67)  = 0.9522.

Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478

Therefore the proportion of children that have an index of at least 110 is 0.0478

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Answer:

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Step-by-step explanation:

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