How to count the total number of users from backend reactjs.

A bin contains 100 sty le a notebooks, 100 style b notebooks, and 100 style c notebooks. antoine will select 3 notebooks from th

emmasim [6.3K]

The answer is Ten. Substituting numbers for letters, available selections are 111, 112, 113, 122, 123, 133, 222, 223, 233, 333. Note that, for example, 112, 121, and 211 are considered as the same selection.
AAA, BBB, CCC, AAB, AAC, BBC, ABB, ACC, CCB & ABC.

7 0

3 years ago

Which tables and fields would you access to determine which book titles have been purchased by a customer and when the order shi

enyata [817]

Answer:

To determine which book titles have been purchased by a customer and when the order shipped the following tables and fields would be used.

Table:

CUSTOMERS

Fields

Customerno

Table

ORDERS

Fields:

Orderno

Shipdate

Customerno

Table:

ORDERITEMS

Fields:

Orderno

Table:

BOOKS

Fields

isbn

title

BOOKS table contains field like title of the books, so this will help in finding which book titles have been purchased.

CUSTOMERS table keeps information about customers that purchasing an ordering the books. The customerno uniquely identifies each customer so that the order information can be found using the customerno of a specific customer.

ORDERITEMS keeps information about orders via orderno

ORDERS table will keep track about the shipment of orders. Orderno identifies each order, shipdate will help determine when an order is shipped.

7 0

3 years ago

Excel solver does not allow for the inclusion of greater than or equal to

GuDViN [60]

Answer:

True

Explanation:

Excel Solver does not allow for the inclusion of greater than or equal to, less than or equal to or equal nomenclature as Excel will not recognize these.

6 0

3 years ago

Use JavaWrite a program that will simulate a change machine found at cash registers. Input the amount due and amount paid from t

Ksju [112]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to accept input from user

public class Main { // class name

public static void main(String [] args) { // start of main method

Scanner input = new Scanner(System.in); // creates Scanner class object to take input from user

System.out.println("Please Enter the Cost of the Item: "); // prompts user to enter the cost of item

double itemCost = input.nextDouble(); //scans and reads the input value of item cost

System.out.println("Please Enter the Amount Paid: "); // prompts user to enter the amount paid

double amount = input.nextDouble(); //scans and reads the value of amount from user

int change = (int)(amount * 100 - itemCost * 100); //compute the remaining amount i.e. change

System.out.println("Change Owed: " + change / 100.0); // displays the owed change

int quarters = change / 25; // computes the value for quarters

change = change % 25; // compute the quarters remaining

int dimes = change / 10; // computes dimes

change = change % 10; // computes dimes remaining

int nickels = change / 5; // computes nickels

change = change % 5; // compute nickels remaining

int pennies = change; // computes pennies

System.out.println("Quarters: " + quarters); // displays computed value of quarters

System.out.println("Dimes: " + dimes); // displays value of dimes

System.out.println("Nickels: " + nickels); // displays value of nickels

System.out.println("Pennies: " + pennies); }} //displays value of pennies

Explanation:

I will explain the program with an examples.

Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:

Change is computed as

change = (int)(amount * 100 - itemCost * 100);

This becomes;

change = (int)(5.00 * 100 - 4.57 * 100)

= 500 - 457

change = 43

Now the change owed is computed as:

change / 100.0 = 43/100.0 = 0.43

Hence change owed = 0.43

Next quarters are computed as:

quarters = change / 25;

This becomes:

quarters = 43/25

quarters = 1

Now the remaining is computed as:

change = change % 25;

This becomes:

change = 43 % 25;

change = 18

Next the dimes are computed from remaining value of change as:

dimes = change / 10;

dimes = 18 / 10

dimes = 1

Now the remaining is computed as:

change = change % 10;

This becomes:

change = 18 % 10

change = 8

Next the nickels are computed from remaining value of change as:

nickels = change / 5;

nickels = 8 / 5

nickels = 1

Now the remaining is computed as:

change = change % 5;

This becomes:

change = 8 % 5

change = 3

At last the pennies are computed as:

pennies = change;

pennies = 3

So the output of the entire program is:

Change Owed: 0.43 Quarters: 1 Dimes: 1 Nickels: 1 Pennies: 3

The screenshot of the output is attached.

7 0

3 years ago

In this chapter, you saw an example of how to write an algorithm that determines whether a number is even or odd. Write a progra

vagabundo [1.1K]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

public class RandomOddEve {

/** Main Method */

public static void main(String[] args) {

int[] nums = new int[100]; // Declare an array of 100 integers

// Store the counts of 100 random numbers

for (int i = 1; i <= 100; i++) {

nums[(int)(Math.random() * 10)]++;

}

int odd = 0, even = 0; // declare even and odd variables to 0, respectively

// Both variables will serve a counters

// Check for odd and even numbers

for(int I = 0; I<100; I++)

{

if (nums[I]%2 == 0) {// Even number.

even++;

}

else // Odd number.

{

odd++;

}

//.Print Results

System.out.print("Odd number = "+odd);

System.out.print("Even number = "+even);

}

8 0

4 years ago

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