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maxonik [38]
2 years ago
5

Solve similar triangles (advanced)

Mathematics
1 answer:
Eddi Din [679]2 years ago
3 0
Triangles ABC and ADE are similar, meaning that
AB/BC=AD/DE
6/5=(6+x)/14
84/5=6+x
X=10.8
So x=10.8
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Given:

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\overrightarrow{a}=2\hat{i}-\hat{j}+\hat{k}

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To find:

The value of |\overrightarrow{a}\times \overrightarrow{b}|.

Solution:

We have,

\overrightarrow{a}=2\hat{i}-\hat{j}+\hat{k}

\overrightarrow{b}=\hat{i}-3\hat{j}+5\hat{k}

The cross product of these two vectors is:

\overrightarrow{a}\times \overrightarrow{b}=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\2&-1&1\\1&-3&5\end{vmatrix}

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|\overrightarrow{a}\times \overrightarrow{b}|=\sqrt{(-2)^2+(-9)^2+(-5)^2}

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Genrish500 [490]
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