If STUV is a rectangle and m_VSU = 52°, what is the value of x?
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Answer:
The Area of the base is 16 cm² .
Step-by-step explanation:
Given as :
The surface area of the cuboid = x = 95 cm²
The lateral surface area of the cuboid = y = 63 cm²
Let The Area of the base = z cm²
Now, Let The length of cuboid = l cm
The breadth of cuboid = b cm
The height of cuboid = h cm
<u>According to question</u>
∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)
Or, x = 2 ×(l × b + b × h + h × l)
Or, 95 = 2 ×(l × b + b × h + h × l)
Or, (l × b + b × h + h × l) = ....1
<u>Similarly</u>
∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)
Or, y = 2 ×(b × h + l × h)
Or, 2 ×(b × h + l × h) = 63
Or, (b × h + l × h) = ......2
Putting value of eq 2 into eq 1
so, (l × b + ) =
Or, l × b = -
Or, l × b =
i.e l × b =
so, l × b = 16
<u>Now, Again</u>
∵The Area of the base = ( length × breadth ) cm²
So, z = l × b
i.e z = 16 cm²
So, The Area of the base = z = 16 cm²
Hence,The Area of the base is 16 cm² . Answer