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miss Akunina [59]
3 years ago
7

William hikes at a constrant rate , converting 6 miles in 2 hours, which expression represents how many miles william hikes in 4

hours?
A). 1/3 h
B). 1/2 h
C). 2h
D). 3h
Mathematics
1 answer:
yulyashka [42]3 years ago
6 0
The answer is D
6/2=3 miles per hour
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professor190 [17]

Answer:

100

Step-by-step explanation:

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Is (1, 2) a solution to this system of equations? 10x + 4y = 18 x + 9y = 19
Arlecino [84]

Answer:

Yes

Step-by-step explanation:

The intersection point of 10x+4y=18 and x+9y=19 is (1,2) on a graph.

3 0
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Are these two triangles congruent please help I will mark brainliest
sergeinik [125]
No. Angles don’t correspond to one another.
Therefore, they are not congruent
4 0
3 years ago
A truck driver can travel 560 miles on 28 gallons of gas. How far can he travel on 35 gallons of gas?
Shtirlitz [24]
560 / 28 = 20....so the driver travels 20 miles per gallon

on 35 gallons......35 * 20 = 700 miles <==

or u can also do it this way...

560/28 = x / 35....560 miles to 28 gal = x miles to 35 gal
cross multiply because this is a proportion
(28)(x) = (560)(35)
28x = 19600
x = 19600/28
x = 700 miles <==

so u can either do it by finding the unit rate or by making a proportion. either way will result in the same answer.
8 0
4 years ago
(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa
mr Goodwill [35]

Answer:

a) \frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}

b) P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform Y\sim Unif(A,B). And the density function would be given by:

f(x) =\frac{1}{B-A} , A

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}

And we can find the probability desired like this:

P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)

And from the cumulative distribution function of X ficen by F(X)\frac{X-A}{B-A} we got:

\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}

Part b

For this case we assume that X\sim Gamma (2,1)

On this case we assume that \alpha=2, \beta= 1

The density function for the Gamma distribution is given by:

P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}

And on this case we can find the probability using the complement rule like this:

P(X>1) = 1-P(X\leq 1)=0.736

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736

6 0
3 years ago
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