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1 year ago

Plase help I need it

Mathematics

1 answer:

grigory [225]1 year ago

3 0

Answer:

it's an estimate within 10 degrees so I estimate that that angles is 5 degrees

Step-by-step explanation:

5 degrees

Hoped that helped

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Mr.russo exchanged 200 euros for 270 dollars how many dollar he get foe 300 euros

dimulka [17.4K]

We must fine the conversion for this, so we have to divide $270 by 200€ to get 1.35 Dollars for every Euro..
Now we multiply 300 by 1.35 to get 405 dollars

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2 years ago

Read 2 more answers

(-2-3 radical2) (5-4i radical2)

gavmur [86]

* means multiply, sqrt=radical
expand
-10+sqrt2*8i-sqrt2*15+24i
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2 years ago

PLEASE HELP 40 POINTS !!!

spin [16.1K]

Answer:I think the answer is c

Step-by-step explanation:

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2 years ago

HELP!!!<br> Find the circumference. Don't forget to label your answer.

bija089 [108]

<h2><u>CIRCUMFERENCE</u></h2>

<h3>Possible Question:</h3>

» The diameter of a circle is 11 in. What is the circle's circumference?

<h3>Answer:</h3>

$\blue{\bold{34.54 \: \:in}}$

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

To find the circumference, use pi (π), a mathematical constant. Its value is approximately equal to 3.14.

— Multiply the diameter with π in order to get the circumference of a Circle.

$\sf \: given : \underline{ \tt \: d = 11 \: in \: } \\ \\ \tt \: \: C = π × d \tt \\ \tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14×11 \: in \\ \tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \underline{ \boxed{ \purple{ \bold{ 34.54\:in}}}}$

Therefore, the circumference of the circle is 34.54 inches.

_______________∞_______________

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1 year ago

What is (2+y)³ written out?

Karolina [17]

(2x + y)³
(2x + y)(2x + y)(2x + y)
(2x(2x + y) + y(2x + y))(2x + y)
(2x(2x) + 2x(y) + y(2x) + y(y))(2x + y)
(4x² + 2xy + 2xy + y²)(2x + y)
(4x² + 4xy + y²)(2x + y)
4x²(2x + y) + 4xy(2x + y) + y²(2x + y)
4x²(2x) + 4x²(y) + 4xy(2x) + 4xy(y) + y²(2x) + y²(y)
8x³ + 4x²y + 8x²y + 4xy² + 2xy² + y³
8x³ + 12x²y + 6xy² + y³

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2 years ago

Plase help I need it​

Plase help I need it