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netineya [11]
3 years ago
14

Plase help I need it​

Mathematics
1 answer:
grigory [225]3 years ago
3 0

Answer:

it's an estimate within 10 degrees so I estimate that that angles is 5 degrees

Step-by-step explanation:

5 degrees

Hoped that helped

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PLS HELP! ASAP!
iris [78.8K]

Answer:

AC

Step-by-step explanation:

It would be the longest straight line segment that passes through the center of the circle and have end points that lie on the circle.

3 0
3 years ago
Read 2 more answers
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Vedmedyk [2.9K]

Answer:

30

Step-by-step explanation:

  1. How much was the decrease from Figure A to Figure B (let x be the decrease): 45x = 27
  2. Divide each by 45 to cancel out the 45 next to x. It should now look like this: x = 3/5
  3. To find x, we would normally multiply x by 3/5, but because we don't have x, we just DIVIDE 18 by 3/5: 18 ÷ 3/5 = 30
  4. So, x = 30

I hope this helps!

7 0
3 years ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
3 years ago
A test of hypothesis is conducted to determine whether annual income and education level are independent. It is determined that
kramer

Answer: We concluded that annual income and education level are not independent.

Step-by-step explanation:

For the given situation, the null and alternate hypothesis can be formulated as:

H_0: annual income and education level are independent.

H_a: annual income and education level are not independent.

Given,  the value of test statistic is 24.32 and the critical value of test statistics is 13.32.

i.e. the test statistic value is greater than the critical value, thus we have enough evidence to reject the null hypothesis.

Therefore, we reject null hypothesis .

So , we concluded that annual income and education level are not independent.

5 0
4 years ago
Find the measure of the given angle a= x 16 d=2x
saw5 [17]
Sorry, i'm not sure :(
5 0
3 years ago
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