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3 years ago

A monopolist is likely to _ and__than a comparable perfectly competitive firm.

Mathematics

1 answer:

OLga [1]3 years ago

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7.865 rounded to the nearest whole number

Sholpan [36]

Answer:

Step-by-step explanation:

Since the first decimal place is greater than 5, it rounds to 8, because 8 is the next whole number to 7.

If my answer is incorrect, pls correct me!

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-Chetan K

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3 years ago

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EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If

amm1812

Answer:

To Prove: $9e^x$ is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If $f(x) = 9e^x$ , then $f ^{(n + 1)(x)} =9e^x$ for all n. If d is any positive number and |x| ≤ d, then $|f^{(n + 1)(x)}| = 9e^x\leq 9e^d.$

So Taylor's Inequality, with a = 0 and M = $9e^d$ , says that $|R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq d.$

Notice that the same constant $M = 9e^d$ works for every value of n.

But, since $lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$$ ,

We have $lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0$

It follows from the Squeeze Theorem that $lim_{n\to\infty} |R_n(x)|=0$ and therefore $lim_{n\to\infty} R_n(x)=0$ for all values of x.

$THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and $ lim_{n\to\infty} R_n(x)=0 \: for \: |x-a|$

By this theorem above, $9e^x$ is equal to the sum of its Maclaurin series, that is,

$9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}$ for all x.

6 0

3 years ago

How do you do it i am very confused/ i just need the answer lol

nydimaria [60]

Answer:

No question!

Step-by-step explanation:

Hi! Could you please insert a question so I could answer for you?

I would love to help!

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2 years ago

Solve the trigonometry equation cos4x+cos2x

Amanda [17]

$2 \cos(3x) \cos(x)$

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3 years ago

Simplify -8(3y + 5) - 3 A.24y + 35 B.-24y - 80 C.-24y - 43 D.-24y - 40

tatiyna

Answer:

answers is C

Step-by-step explanation:

3 0

3 years ago

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A monopolist is likely to _______ and________than a comparable perfectly competitive firm.

A monopolist is likely to _ and__than a comparable perfectly competitive firm.