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babunello [35]
3 years ago
15

What numbers are both squared and cubed numbers​

Mathematics
1 answer:
vichka [17]3 years ago
6 0

Answer:

1,4&9

Step-by-step explanation:

1,4and9 are the first three square numbers, Their cubes are therefore both squares and cubes.

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4.2 = 1.4y
BlackZzzverrR [31]

Answer

y = 1.4

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6 0
3 years ago
Use euler’s formula to find the missing number faces :20 edges : 30 vertices ______
Mamont248 [21]

Answer:

8 Faces

Step-by-step explanation:

The Euler’s formula is:

V-E+F=2

Where V is number of vertices, E is number of edges and F is number of faces.

In our example, E=20, V=30, so we have:

30-20+F=2

10-F=2

F=8

4 0
3 years ago
Eliminate the parameter of the following equations and write in rectangular form in terms of x and y.
rosijanka [135]

Solve for cos(t) and sin(t):

x = 2 + 3 cos(t)   ⇒   cos(t) = (x - 2)/3

y = 1 - sin(t)   ⇒   sin(t) = 1 - y

Recall the Pythagorean identity,

sin²(t) + cos²(t) = 1

It follows that

((x - 2)/3)² + (1 - y)² = 1

or

(x - 2)²/9 + (y - 1)² = 1

5 0
3 years ago
The radius of a circle is 5 in. Find its area to the nearest tenth. Answer: A = 1 in? Submit Answer​
eimsori [14]

First Answer:

Area= 78.54

Step-by-step explanation:

A=πr^2

pi = 3.14

8 0
3 years ago
AB has a midpoint M at (6, 3). If point A is at (-5, -1) & point B is at (2a - 7, b + 7), find the value of b
horsena [70]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
A(\stackrel{x_1}{-5}~,~\stackrel{y_1}{-1})\qquad
B(\stackrel{x_2}{2a-7}~,~\stackrel{y_2}{b+7})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{(2a-7)-5}{2}~~,~~\cfrac{(b+7)-1}{2} \right)=\stackrel{\stackrel{midpoint}{M}}{(6,3)}\implies \begin{cases}
\cfrac{(2a-7)-5}{2}=6\\[-0.5em]
\hrulefill\\
\cfrac{(b+7)-1}{2}=3\\[0.8em]
(b+7)-1=6\\
b+6=6\\
\boxed{b=0}
\end{cases}

4 0
4 years ago
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