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uranmaximum [27]
2 years ago
14

How can you use the Distributive Property to check your work when factoring?

Mathematics
2 answers:
vitfil [10]2 years ago
6 0
The answer is d. Once an expression has been factored, use the distributive property to expand the expression. The expanded expression should be the original expression.
Mademuasel [1]2 years ago
3 0
The answer is D. Once an expression has been factored, use the Distributive Property to expand the expression. The expanded expression should be the original expression.
You might be interested in
If y = kx, what is the value of k if y = 20 and x = 0.4?
True [87]
Set up an equation 20=k(0.4)....to find k divide 20 by 0.4
8 0
3 years ago
What is the scale factor of the dilation shown? Quadrilateral D E F G has side lengths 4, 10, 8, and 4. Quadrilateral D prime E
ira [324]

Answer:

i think the scale factor is 3:2

Step-by-step explanation:

To figure the total difference divide:

6 divided by 4 = 1.5

1.5 = 3/2

pls tell me if wrong

Hope this helps

8 0
3 years ago
The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form
Alex

The other format for straight-line equations is called the "point-slope" form. For this one, they give you a point <span>(x1, y1)</span><span> and a slope </span>m, and have you plug it into this formula:

<span><span>y </span>–<span> y</span>1<span> = m</span>(<span>x </span>–<span> x</span>1)</span>

Don't let the subscripts scare you. They are just intended to indicate the point they give you. You have the generic "x" and generic "y<span>" that are always in your equation, and then you have the specific </span>x<span> and </span>y<span> from the point they gave you; the specific </span>x<span> and </span>y<span> are what is subscripted in the formula. Here's how you use the point-slope formula:</span>

<span><span>Find the equation of the straight line that has slope </span><span>m = 4</span><span> and passes through
the point </span>(–1, –6).</span><span><span>This is the same line that I found on the </span>previous page<span>, so I already know what the answer is (namely, </span><span>y = 4x – 2</span>). But let's see how the process works with the point-slope formula.<span>They've given me </span><span>m = 4, x1 = –1,</span><span> and </span><span>y1 = –6</span>.  I'll plug these values into the point-slope form, and solve for "<span>y=</span>":<span><span><span>y </span>–<span> y</span>1 = m(<span>x </span>–<span> x</span>1)
y – (–6) = (4)(x – (–1))
y + 6 = 4(x + 1)
y + 6 = 4x + 4
y = 4x + 4 – 6</span><span>y = 4x – 2</span> Copyright © Elizabeth Stapel 2000-2011 All Rights Reserved</span></span>

This matches the result I got when I plugged into the slope-intercept form. This shows that it really doesn't matter which method you use (unless the text or teacher specifies). You can get the same answer either way, so use whichever method works more comfortably for you.

<span>You can use the Mathway widget below to practice finding a line equation using the point-slope formula. Try the entered exercise, or type in your own exercise. Then click "Answer" to compare your answer to Mathway's. (Or skip the widget and continue with the lesson.)</span>

7 0
3 years ago
Read 2 more answers
Cosθ=−2√3 , where π≤θ≤3π2 .
Alex787 [66]

Answer:

sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}

Step-by-step explanation:

step 1

Find the  sin(\theta)

we know that

Applying the trigonometric identity

sin^2(\theta)+ cos^2(\theta)=1

we have

cos(\theta)=-\frac{\sqrt{2}}{3}

substitute

sin^2(\theta)+ (-\frac{\sqrt{2}}{3})^2=1

sin^2(\theta)+ \frac{2}{9}=1

sin^2(\theta)=1- \frac{2}{9}

sin^2(\theta)= \frac{7}{9}

sin(\theta)=\pm\frac{\sqrt{7}}{3}

Remember that

π≤θ≤3π/2

so

Angle θ belong to the III Quadrant

That means ----> The sin(θ) is negative

sin(\theta)=-\frac{\sqrt{7}}{3}

step 2

Find the sec(β)

Applying the trigonometric identity

tan^2(\beta)+1= sec^2(\beta)

we have

tan(\beta)=\frac{4}{3}

substitute

(\frac{4}{3})^2+1= sec^2(\beta)

\frac{16}{9}+1= sec^2(\beta)

sec^2(\beta)=\frac{25}{9}

sec(\beta)=\pm\frac{5}{3}

we know

0≤β≤π/2 ----> II Quadrant

so

sec(β), sin(β) and cos(β) are positive

sec(\beta)=\frac{5}{3}

Remember that

sec(\beta)=\frac{1}{cos(\beta)}

therefore

cos(\beta)=\frac{3}{5}

step 3

Find the sin(β)

we know that

tan(\beta)=\frac{sin(\beta)}{cos(\beta)}

we have

tan(\beta)=\frac{4}{3}

cos(\beta)=\frac{3}{5}

substitute

(4/3)=\frac{sin(\beta)}{(3/5)}

therefore

sin(\beta)=\frac{4}{5}

step 4

Find sin(θ+β)

we know that

sin(A + B) = sin A cos B + cos A sin B

so

In this problem

sin(\theta + \beta) = sin(\theta)cos(\beta)+ cos(\theta)sin (\beta)

we have

sin(\theta)=-\frac{\sqrt{7}}{3}

cos(\theta)=-\frac{\sqrt{2}}{3}

sin(\beta)=\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute the given values in the formula

sin(\theta + \beta) = (-\frac{\sqrt{7}}{3})(\frac{3}{5})+ (-\frac{\sqrt{2}}{3})(\frac{4}{5})

sin(\theta + \beta) = (-3\frac{\sqrt{7}}{15})+ (-4\frac{\sqrt{2}}{15})

sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}

8 0
3 years ago
Which of the following sets of numbers could represent the three sides of a triangle?
kupik [55]

Answer:

B-7,22,28

Step-by-step explanation:

The sum of the smaller numbers must be greater than the larger number, if not then the answer is wrong.

6 0
2 years ago
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