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2 years ago

How can you use the Distributive Property to check your work when factoring?

2 answers:

6 0

The answer is d. Once an expression has been factored, use the distributive property to expand the expression. The expanded expression should be the original expression.

Mademuasel [1]2 years ago

3 0

The answer is D. Once an expression has been factored, use the Distributive Property to expand the expression. The expanded expression should be the original expression.

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The world’s population is currently estimated at 7,125,000,000. What is this to the nearest billion? billion

Oksana_A [137]

Answer:

7,000,000,000

Step-by-step explanation:

since the closest number is less than 5 (1<5) you round down making the nearest billion 7

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3 years ago

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Please help on this i cant understand it

poizon [28]

Answer:

to get the probability you add the number of figure all together

divide the number of spheres with the total

2 ÷ 10

you get 1÷ 5

you get the answer as 0.2

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2 years ago

Amelia rented a DVD and it was due to be returned on 26 Nov. She actually returned it to the shop on 12 Dec. The rental shop app

svet-max [94.6K]

Answer:

144 (pounds? euros? idk what currency it is)

Step-by-step explanation:

there are 16 day between the date. 16 x 9 = 144

6 1

3 years ago

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The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

3 years ago

Mr. Grant's class is working on a recycling project. The students are collecting aluminum cans. Over 3 days, they collected 88 c

blsea [12.9K]

About 270 cans over the 3 days

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3 years ago

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