The vertical velocity of the car at the given position and time is 4.905 m/s.
The given parameters:
- Initial angular velocity,
= 6.3 rad/s - Time of motion, t = 0.25 s
- Vertical displacement, y = 0.75 m
- Angular acceleration,

<h3>What is vertical velocity?</h3>
- This is the linear velocity of an object in a vertical direction.
The angular velocity of an object in a circular motion is given as;

The vertical velocity of the car at the given position and time is calculated as follows;

Thus, the vertical velocity of the car at the given position and time is 4.905 m/s.
Learn more about vertical velocity here: brainly.com/question/7358392
Answer:
20000*(1+15%)³=30417.5
Explanation:
The number $40000 is irrelevant. Don't be disturbed!
This is a typical compound interest question. Use the compound interest formula: S=p(1+<em>i)ⁿ</em>
S for sum, p for principal balance, <em>i </em>for interest rate, n for the number of years or times
The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
Read more on pH here; brainly.com/question/22390063
The method of SMART goals (an acronym for the 5 steps of specific, measurable, attainable, relevant, and time-based goals) is one of the most effective tools used by high achievers to reach their business goals consistently.
First calculate the change in y over the change in x:
by - ay -1 - 1 -2
———— = ——— = —— = 1
bx - ax -2 - 0 -2
The slope is 1:
Second set up the equation in y = mx + b form (m is your slope!) ...
y = (1)x + b
... and plug in either point you have used (A or B)
A(0,1)
1 = (1)(0) + b
1 = b
Now you have your equation: y = 1x + 1
Your final step is to plug in point C to solve for your missing variable:
y = (1)(5) + 1
y = 6
the value of H therefore is 6