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____ [38]
4 years ago
6

Select the correct answer from each drop-down menu.

Mathematics
1 answer:
Lorico [155]4 years ago
7 0

Answer:

A)Multiply both sides by 3x + 7.

Reset

A)the solution of the equation is  x=-12

Step-by-step explanation:

Hello

let

to begin isolating we must multiply both sides by 3x + 7.

Reset

this way

\frac{-22+3x}{3x+7}=2\\\frac{-22+3x}{3x+7}*(3x+7)=2*(3x+7)\\-22+3x=2*(3x+7)

let´s continue to find x

\\-22+3x=2*(3x+7)\\-22+3x=6x+14\\-22-14=6x-3x\\-36=3x\\x=\frac{-36}{3}\\ x=-12

the solution of the equation is x=-12

have a great day

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11/4 x 7/3 as a fraction in simplest form
nata0808 [166]

Answer:

77/12

Step-by-step explanation:

11×7/ 4×3

77/4×3

=77/12

3 0
2 years ago
I’ll put you as brainliest
kari74 [83]

The law of an object moving with constant acceleration is

s(t)=s_0+v_0t+\dfrac{1}{2}at^2

Where s is space, t is time, s_0 is the initial position, v_0 is the initial velocity and a is the acceleration.

In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).

So, its law is

h(t)=100t-\dfrac{1}{2}gt^2

(I changed s for h since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).

The rocket hits the ground if its height is zero, so if we set h=0 we have

0=100t-\dfrac{1}{2}gt^2 \iff t(100-\dfrac{1}{2}gt)=0

Solving for t, we have either t=0, or

100-\dfrac{1}{2}gt=0 \iff 100=\dfrac{1}{2}gt \iff 200=gt \iff t=\dfrac{200}{g}

The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have

t=\dfrac{200}{g}\approx \dfrac{200}{32.2}\approx 6.21

3 0
3 years ago
Four less than the product of two and a number is less than the product of four and the same number increased by eight. What is
Anit [1.1K]

Answer:

2n - 4 < 4n + 8

I believe this is the algebraic expression for the problem. :)

8 0
3 years ago
Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not
Verizon [17]

Answer: \left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3-2}{4-1}

   = -\frac{5}{3}

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = -\frac{5}{3}(x - 1)

y - 2 = -\frac{5}{3}x + \frac{5}{3}

y      = -\frac{5}{3}x + \frac{11}{3}

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ -\frac{5}{3}x + \frac{11}{3}

8 ___ -\frac{5}{3}(-2) + \frac{11}{3}

8 ___ \frac{1}{3}

8 > \frac{1}{3}

so ≤ makes the statement False

⇒ y ≤ -\frac{5}{3}x + \frac{11}{3}

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.  

y < 8   or  x > -2 are two examples.


---> I just realized that the system can be simpler than what I did above:

\left \{ {{x>-2} \atop {y < 8}} \right



4 0
4 years ago
An elevator in a hotel moves at 20 feet per second. leaving from the ground floor, its height in feet after t seconds is given b
Lisa [10]

Answer:

After 7.5 seconds and a height of 0

Step-by-step explanation:

8 0
4 years ago
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