Answer:
1234588765
Step-by-step explanation:
O=4i (is that was you were asking about)
edit: sorry that wasn't very detailed say if the input is 4 the output will be 16 or if the input is 100 the output will be 400. So mainly what ever the input is multiply it by 4.
I hope this helps :)
2a + 3b = 6 --> Equation 1
5a + 2b = 4 --> Equation 2
Equation 1 * 5 --> 10a + 15b = 30
Equation 2 * 2 --> 10a + 4b = 8
Equation 1 - Equation 2 --> 11b = 22 --> b = 2
Sub b=2 in Equation 1 (or 2, either works):
2a + 3b = 6
2a + 3(2) = 6
2a + 6 = 6
2a = 0
a = 0
b = 2, a = 0
Answer:
Step-by-step explanation:
What i would do is multiply both sides by 2z + 1
so you get z-6=20z+10
-19z=16
z=-16/19
Answer:
9 Quarters
8 Dimes
3 Nickels
Step-by-step explanation:
We let the number of quarters be q
number of dimes be d
and
number of nickels be n
Since quarters are worth 0.25, dimes are worth 0.10 and nickels are worth 0.05 and total worth is 3.20, we can write an equation as:
0.25q + 0.10d + 0.05n = 3.20
Next,
3 times as many quarters as Nickels, we can write:
q = 3n
and
5 more dimes than nickel, we can write:
d = n + 5
Substituting these last 2 equations in the first and solving for n gives us:
0.25q + 0.10d + 0.05n = 3.20
0.25(3n) + 0.10(n+5) + 0.05n = 3.20
0.75n + 0.10n +0.5 + 0.05n = 3.20
0.9n = 2.70
n = 2.70/0.9 = 3
n = 3
We know q = 3n, so
q = 3(3) = 9
Also, we know d = n + 5, which means:
d = 3 + 5 = 8
Thus,
There are:
9 Quarters
8 Dimes
3 Nickels
