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4 years ago

Ax over b plus cx over d equals e solve for x

1 answer:

7 0

$\frac{ax}{b}+\frac{x}{d}=e\ \ \ \ \ \ |multiply\ both\ sides\ by\ "bd"\\\\bd\times\frac{ax}{b}+bd\times\frac{cx}{d}=bde\\\\adx+bcx=bde\\\\(ad+bc)x=bde\ \ \ \ \ |divide\ both\ sides\ by\ (ad+bc)\\\\\boxed{x=\frac{bde}{ad+bc}}$

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What are the values of x and y

Murljashka [212]

E 10 12

x=18*5)14. x=40/4. x=10. y=(15*4)/5 y=60/5 y=12.

resposta : 10 e 12

4 0

3 years ago

Solve a math problem

mars1129 [50]

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7 0

4 years ago

Read 2 more answers

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP HURRY (show work pls

ycow [4]

Answer is b. -1/2
worked it out in the pic

5 0

3 years ago

Read 2 more answers

The angles in a triangle are 100, 40, and 40 degrees. Classify the triangle by its angles and sides.

lara [203]

Answer:

F. Obtuse isosceles

Step-by-step explanation:

Since we have an angle that is 100 degrees, we have an obtuse angle

We have two angles that are 40, which means we have two sides that are equal length, because two angles have the same measure. That means it is isosceles

The triangle is an obtuse isosceles

8 0

3 years ago