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aleksandrvk [35]
4 years ago
7

Ax over b plus cx over d equals e solve for x

Mathematics
1 answer:
Lorico [155]4 years ago
7 0
\frac{ax}{b}+\frac{x}{d}=e\ \ \ \ \ \ |multiply\ both\ sides\ by\ "bd"\\\\bd\times\frac{ax}{b}+bd\times\frac{cx}{d}=bde\\\\adx+bcx=bde\\\\(ad+bc)x=bde\ \ \ \ \ |divide\ both\ sides\ by\ (ad+bc)\\\\\boxed{x=\frac{bde}{ad+bc}}
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Find the MAD of this set of data.
barxatty [35]

Answer:

2.8

Step-by-step explanation:

The given data set is;

6, 12, 10, 9, 8, 6, 2, 4, 8, 15

The mean of this set is;

\bar X=\frac{\sum x}{n}

\bar X=\frac{6+12+10+9+8+6+2+4+8+15}{10}

\bar X=\frac{80}{10}=8

The mean absolute deviation is given by

M.A.D=\frac{\sum |x-\bar X|}{n}

M.A.D=\frac{|6-8|+|12-8|+|10-8|+|9-8|+|8-8|+|6-8|+|2-8|+|4-8|+|8-8|+|15-8|}{10}

M.A.D=\frac{2+4+2+1+0+2+6+4+0+7}{10}

M.A.D=\frac{28}{10}

M.A.D=2.8

5 0
4 years ago
The professor of a large probability class randomly selected 8 students and asked the amount of time (in hours) spent for her co
Alekssandra [29.7K]

Answer:a. μ = 9.667 hours

b. σ = 1.972 hours

c. SE = 0.805 hour

Sample size (n) = 6

Sample data (xi) = 10, 8, 9, 7, 11, 13

a. Mean time spent in a week for this course by students:

Sample mean is given by:

Mean time spent in a week per student is 9.667 hours

b. Standard deviation of the time spent in a week for this course by students:

Standard deviation is given by:

c. Standard error of the estimated mean time spent in a week for this course by students:

Standard error is given by:

6 0
3 years ago
Sam owns a chain of fast food restaurants that operated 200 stores in 1999. If the rate of increase is 8% annually, how many sto
yawa3891 [41]

Answer:

370 stores

Step-by-step explanation:

Given data

initial number of stores P= 200

r= 8%

t= 1999-2007=  8 years

Let us apply the compound interest expression to find the final amount of stores

A= P(1+r)^t

A= 200(1+0.08)^8

A= 200(1.08)^8

A= 200*1.85

A=370

Hence the number of stores in 2007 is 370 stores

4 0
3 years ago
Find the length of UW(with a line over it) if W is between U and V, UV = 16.8 centimeters, and VW = 7.9 centimeters.
stealth61 [152]

Answer:

8.9 cm

Step-by-step explanation:


We have
\overline {UV} = 16.8 cm\\\\\overline {WV} = 7.9 cm\\\\ Since all lines are scalars, \overline{WV} = \overline{VW}\\\textrm{We see that \overline{UW} + \overline{WV} = \overline{UV}\\\\\overline {UW} \\ = \overline {UV} - \overline {WV} = 16.9 - 7.9 = 8.9 cm}

7 0
1 year ago
The cost of printing a catalog of the products that your company distributes is a flat rate of $52 plus $0.20 per copy. Let C re
Delvig [45]

Answer:

1045384620173418506891046 number of copies

Step-by-step explanation:

10464929103984753671930600 ×55215278300

5 0
4 years ago
Read 2 more answers
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