Answer:
hshdnndn
Step-by-step explanation:
hshsbsbbssisisjjs
Answer:
7/12.
Step-by-step explanation:
=x/x+5.
x-5/x+5+4=⅛
x-5/x+9=⅛
x-5=⅛(x+9)
x-5=⅛x+1⅛
x-⅛x=1⅛+5
⅞x=49/8
7x=49
x=7
thus the initial fraction is x/x+5= <u>7</u><u>/</u><u>1</u><u>2</u>
A rational number is a fraction
Answer:
A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones
Step-by-step explanation:
B. table : (8,8)(12,12)(14,16)(16,16)
look at ur points...when x = 8, y = 8...so the table, when x = 8 has a
value of 8
relation : f(x) = 8x - 5....when x = 8
f(8) = 8(8) - 5
f(8) = 64 - 5
f(8) = 59....and the relation has a value of 59
Therefore, the relation has a greater value when x = 8 <==
C. f(x) = 8x - 5...when f(x) = 19
19 = 8x - 5
19 + 5 = 8x
24 = 8x
24/8 = x
3 = x <==
300 is 10 times as much as 30.
because if you do 30 x 10 you get 300
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
