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kap26 [50]
3 years ago
10

Youmin has accounts receivable of $95,400 at march 31, 2021 (amounts in thousands). Credit terms are 2/10, n/30. At march 31, 20

21, there is a $2,100 credit balance in allowance for doubtful accounts prior to adjustment. The company uses the percentage‐of‐receivables basis for estimating uncollectible accounts. The company's estimates of bad debts are as shown below.
SAT
1 answer:
Elodia [21]3 years ago
6 0

Based on the information given bad debt expense is $8,675 and the journal entry is: Debit Bad debt  $6,575; Credit Allowance for Doubtful Account $6,575.

<h2>a. Bad debt expense:</h2>

Accounts Receivable   Amount       %          Estimated Uncollectible

Current                          $65,000         2%              $1,300

1–30 days past due      $12,900          5%              $645

31–90 days past due    $10,100          30%            $3,030

Over 90 days past due $7,400          50%            $3,700

Total                                                                         $8,675

<h2>b. Journal entry:</h2>

March 31 2021

Debit Bad debt  $6,575

Credit Allowance for Doubtful Account $6,575

($8,675-$2,100)

Inconclusion bad debt expense is $8,675 and the journal entry is: Debit Bad debt  $6,575; Credit Allowance for Doubtful Account $6,575.

Learn more about bad debt expense here:brainly.com/question/24871617

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A 10-foot tree casts a 17-foot shadow directly down a slope when the angle of elevation of the sun is 42o (see figure). Find \th
inna [77]

The angle of elevation of the ground is the angle between the ground and the line of sight

The angle of elevation of the ground is 30.46 degrees

<h3>How to calculate the angle of elevation</h3>

The angle of elevation is calculated using the following tangent ratio

\tan(\theta) = \frac{10}{17}

Evaluate the quotient

\tan(\theta) = 0.5882

Take the arc tan of both sides

\theta = \tan^{-1}(0.5882)

Using a calculator, we have:

\theta = 30.46

Hence, the angle of elevation of the ground to the nearest tenth of a degree is 30.46 degrees

Read more about elevation and distance at:

brainly.com/question/7243416

6 0
3 years ago
Select the correct answer.
Amanda [17]

Answer:

a

Explanation:

6 0
3 years ago
What approximate focal length of the objective lens will give a total magnification of 200×? assume a length l = 160 mm.
Viefleur [7K]

Considering the data in the question, the focal length of the objective lens that will give a total magnification of 200x is <u>0.8cm focal length.</u>

The whole question is:

You are using a microscope with a 10x eyepiece. What focal length of the objective lens will give a total magnification of 200x? Assume a length L = 160mm.

<h3>How was the answer derived?</h3>

Given that total magnification is 200

And the Assume length is 160

Since we used a microscope with a 10x eyepiece, the magnification would be divided by 10.

=> 200 ÷ 10 = 20.

Also, the focal length is measured in centimeters or meters; we would change the millimeters of focal length to centimeters. Therefore, we have 160 ÷ 10 = 16

The formula for the focal length of the objective lens = assumed length ÷ total magnification.

=> 16 ÷ 20 = 0.8cm.

Hence, in this case, it is concluded that the correct answer is "0.8cm."

Learn more about the focal length of the objective lens here: brainly.com/question/15744335

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