Answer:
Step-by-step explanation:
<u>Given</u>
- Q(s) = -4s^3 + 7s^2 - 24;
- s = -4 and 1
<u>Verifying zeroes</u>
Q(-4) =
- -4(-4)^3 + 7(-4)^2 - 24 =
- 256 + 112 - 24 =
- 344
- Incorrect as 344 ≠ 0
Q(1) =
- -4(1)^3 + 7(1)^2 - 24 =
- -12 + 7 - 24 =
- -29
- Incorrect as -29 ≠ 0
Step-by-step explanation:
here
f(x)=x^2+6
Now
Replacing the value of x
f(3x)=3x^2 +6
The s um is positive because 11/12 is greater than 7/8
Answer:
x+2 is a factor of 
Step-by-step explanation:
To check: If (x+2) is a a factor of the polynomial 
We need to check if x = -2 is the FACTOR of the given polynomial.
⇒ To show: f (-2) = 0
Now

Since, f(-2) = 0
⇒ -2 is the ROOT of the Polynomial f(x).
⇒(x +2) is the factor of the given polynomial.
Hence, x+2 is a factor of 