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tekilochka [14]
2 years ago
6

The center of a hyperbola is (-4,7), and one vertex is (-2,7). The slope of one of the asymptotes is 2. What is the equation of

the hyperbola in standard form?
Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0

Answer:

Step-by-step explanation:

The center and vertex are horizontally aligned.

a = distance between center and vertex = 2

center (h,k)

asymptotes: y = ±(b/a)x + k∓(b/a)h

(x-h)²/a² - (y-k)²/b² = 1

(x+4)²/2² - (y-7)²/4² = 1

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Solve for X. Grade 7 math.
Dimas [21]

Answer:

x=8

Step-by-step explanation:

9x - 8 = 64 (being vertically opposite angles)

9x = 64 + 8

x=72/9

x=8

9x -8

9*8 -8

72-8

64

8 0
3 years ago
Because you are working a late shift, you will get an increase in your wage. You will get and additional 10% per hour from 6:00p
siniylev [52]

CHECK THE COMPLETE QUESTION BELOW:

Supervisor: "Because you are working a late shift, you will get an increase in your wage. You will get an additional 10% per hour from 6:00 PM to 12:00 AM and additional 15% from 12:00 AM to 1:00 AM." Employee: "I am working from 2:00 PM to 12:00 AM. Between 2:00 PM and 6:00 PM, I will make $12.00 per hour. Between 6:00 PM and 12:00 AM, I will make __________ per hour

Answer:

I will make $13.2 per hour

Explanation:

It can be deducted from the question that that the money Employee gets money for Working from 2.00 PM to 6.00 PM = $12per hour

Also the Employee gets additional 10% of money for working from 6.00 PM to 12.00 AM which implies that

10% = (10/100)*$12per hour

=$1.2per hour

Again, Employee gets additional 15% of the money for working from 12.00 AM to 01.00 AM which can be calculated as:

15% = (15/100)*$12per hour

=$1.8 per hour

which means that Employee gets additional $1.8 per hour

of the money for working from 12.00 AM to 01.00 AM

Therefore, if Employee works from 2.00 PM to 12.00 AM,

Employee will gets money for Working from 2.00 PM to 6.00 PM as well as the 10\% extra wage which

= $12 + $1.2 = $13.2

= \$ 12 + \$ 1.2 = \$ 13.2

7 0
3 years ago
Decide if each expression is equivalent to 2^6 or 4^4
11Alexandr11 [23.1K]

\huge\text{Hey there!}

\mathsf{2^6 = 2\times2\times2\times2\times2\times2}\\\mathsf{2\times2\times2\times2\times2\times2}\\\mathsf{2\times2=4}\\\mathsf{4\times4\times4}\\\mathsf{4\times4=16}\\\large\mathsf{16\times4=64}\\\mathsf{2^6 = \bf{64}}

\mathsf{4^4=4\times4\times4\times4}\\\mathsf{4\times4\times4\times4}\\\mathsf{4\times4=16}\\\mathsf{16\times16}\\\mathsf{16\times16=256}\\\mathsf{4^4=\bf{256}}

\boxed{\boxed{\mathsf{Answer: 64\neq 256}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
3 years ago
Ways to subract 32-13=
Nataly [62]
With a calculator or by hand.
6 0
3 years ago
Read 2 more answers
Find the amplitude of the function.<br> y=1/5 sin 4x
Ilia_Sergeevich [38]

Answer:

option b

1.5

Step-by-step explanation:

Given in the question an equation,

y = 1.5sin4x

The amplitude of y=asin(x) represents half the distance between the maximum and minimum values of the function.

Amplitude = |a|

In the equation y = 1.5sin4x, a = 1.5

So, amplitude of graph y = 1.5sin4x = 1.5

6 0
3 years ago
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