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Dmitrij [34]
2 years ago
12

In the circle represented by the equation (x-4)2+(y-3)2=25, the diameter is

Mathematics
1 answer:
saveliy_v [14]2 years ago
7 0
I’m pretty positive the answer is (-3,4)
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8(1/2u+3/4)
netineya [11]

Answer:

4u+3

Step-by-step explanation:  8/1*1/2= 8/2=4u

                                              8/1*3/4= 24/8=3    

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2 years ago
I need help please....
Zina [86]

Answer:

1/10

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Evaluate and simplify tan 15º.
dimulka [17.4K]
Tan(15) = tan(45 - 30) 

= [tan(45) - tan(30) ] / [ 1 + tan(30)tan(45)] 

= (1 - 1/sqrt(3)) /(1 + 1/sqrt(3)) 

= (sqrt(3) - 1)/(sqrt(3) + 1) 

= (sqrt(3) - 1)^2 /(3 - 1)

 = 1/2 [3 + 1 - 2sqrt(3) ] 

= (2 - sqrt(3) )

= 0.27 is your answer
6 0
3 years ago
*20 POINTS*
Paraphin [41]

Answer:

If you want to use the Rational Zeros Theorem, as instructed, you need to use synthetic division to find zeros until you get a quadratic remainder.

P: ±1, ±2, ±3, ±6  (all prime factors of constant term)

Q: ±1, ±7              (all prime factors of the leading coefficient)

P/Q: ±1, ±2, ±3, ±6, ±1/7, ±2/7, ±3/7, ±6/7  (all possible values of P/Q)

Now, start testing your values of P/Q in your polynomial:

f(x)=7x4-9x3-41x2+13x+6

You can tell f(1) and f(-1) are not zeros since they're not = 0Now try f(2) and f(-2):

f(2)=7(16)-9(8)-41(4)+13(2)+6

       112-72-164+26+6 ≠ 0

f(-2)=7(16)-9(-8)-41(4)+13(-2)+6

       112+72-164-26+6 = 0  OK!! There is a zero at x=-2

This means (x+2) is a factor of the polynomial.

Now, do synthetic division to find the polynomial that results from

(7x4-9x3-41x2+13x+6)÷(x+2):

-2⊥ 7   -9   -41    13     6

         -14   46   -10    -6          

      7  -23   5       3     0     The remainder is 0, as expected

The quotient is a polynomial of degree 3:

7x3-23x2+5x+3

Now, continue testing the P/Q values with this new polynomial.  Try f(3):

f(3)=7(27)-23(9)+5(3)+3

      189-207+15+3 = 0  OK!!  we found another zero at x=3

Now, another synthetic division:

3⊥ 7   -23    5     3

          21   -6   -3_

    7    -2    -1    0  

The quotient is a quadratic polynomial:

7x2-2x-1  This is not factorable, you need to apply the quadratic formula to find the 3rd and 4th zeros:

x= (1±2√2)÷7

The polynomial has 4 zeros at x=-2, 3, (1±2√2)÷7

Step-by-step explanation:

7 0
3 years ago
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