Question

ABC is an isosceles triangle,AB=AC an angle BAC = 40⁰ Calculate the other two angles of the triangle.​

Answer 1

Answer:

Hey There!

Let's solve....

$\angle \: ab = bc \\ so \: it \: is \: given \: that \: \\ \angle \: bac = 40 ^{ \degree} \\ \\ so \: \angle \: abc + \angle \: bca \: + \angle \: bac \\ = 180$

We know that...

$\angle \: abc = \angle \: bca \\ so \: it \: is \: \frac{180 - 40}{2} \\ \\ = \frac{ \cancel{140}^{70} }{ \cancel{2}} \\ \\ = 70 \degree$

Angle BCA=70°

$\angle \: acd + \angle \: acb = 180 \degree \\ \therefore \angle \: acd = 180 - 70 \\ = 110 \degree$

I hope it is helpful....

Cheers!________

Answer 2

Answer:

Both 70 degrees

Step-by-step explanation:

The base angles of an isosceles triangle are congruent.

The other 2 angles are each (180 - 40) / 2

= 70 degrees