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kkurt [141]
3 years ago
10

ABC is an isosceles triangle,AB=AC an angle BAC = 40⁰ Calculate the other two angles of the triangle.​

Mathematics
2 answers:
MissTica3 years ago
8 0

Answer:

Hey There!

Let's solve....

\angle \: ab = bc \\ so \: it \: is \: given \: that \: \\   \angle \: bac = 40 ^{ \degree}  \\  \\ so \:  \angle \: abc +  \angle \: bca \:  +  \angle \: bac \\  = 180 \\

We know that...

\angle \: abc =  \angle \: bca \\ so \: it \: is \:  \frac{180 - 40}{2} \\  \\  =  \frac{  \cancel{140}^{70} }{ \cancel{2}}   \\ \\   = 70 \degree

Angle BCA=70°

\angle \: acd +  \angle \: acb = 180 \degree \\  \therefore \angle \: acd = 180 - 70 \\  = 110 \degree \\

<h2>I hope it is helpful....</h2><h3>Cheers!________</h3>

maxonik [38]3 years ago
5 0

Answer:

Both 70 degrees

Step-by-step explanation:

The base angles of an isosceles triangle are congruent.

The other 2 angles are each (180 - 40) / 2

= 70 degrees

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