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Aleksandr-060686 [28]
3 years ago
6

Y = -5x+1 linear or nonlinear

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
It is linear because the x does not have an exponent (which would determine the graph to be a curve) such as x^2, x^3, etc.
PIT_PIT [208]3 years ago
6 0

Answer:

non linear

Step-by-step explanation:

hope helps

You might be interested in
1. A luge race is very dangerous, and a crash can cause serious injuries. The league requires anyone who has a crash to have a t
antiseptic1488 [7]

Answer:

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Step-by-step explanation:

For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain performer has an independent .04 probability of a crash in each race.

This means that p = 0.04

a) What is the probability she will have her first crash within the first 30 races she runs this season

This is:

P(X \geq 1) = 1 - P(X = 0)

When n = 30

We have that:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{30,0}.(0.04)^{0}.(0.96)^{30} = 0.2939

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2939 = 0.7061

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

7 0
2 years ago
Write the equation for a rational function with a hole at x = 6 and
Kisachek [45]

Answer:

x-6/x²-x-30

Step-by-step explanation:

(x-6)(x+5)

x²-x-30

when you factor out  x-6 you have a removable discontinuity and you have x+5 as your denominator and that would be the vertical asymptote since you can have a 0 as your denominator the V.A. would be x = -5.

6 0
3 years ago
Use the given information to find the unknown value:y varies directly as the square of z. When x = 2, then y= 20. Find y when 2
Vladimir79 [104]

Answer

y = 45 when x = 3

Step-by-step explanation:

\begin{gathered} \text{Given that y varies directly as the square of x} \\ \text{This implies that there is a positive relationship betwe}en\text{ y and the square of z} \\ \text{Mathematically, this can be expressed as} \\ y\text{ }\propto x^2 \\ To\text{ turn this expression into an equation, we n}eed\text{ to introduce a proportionality constant k} \\ y=kx^2 \\ \text{ According to the question, y = 20 and x = 2} \\ \text{From the above informaion we can find our k} \\ y=kx^2 \\ 20\text{ = k }\cdot2^2 \\ 20\text{ = k }\cdot\text{ 4} \\ \text{Divide both sides by 4} \\ \frac{20}{4}\text{ = }\frac{k\cdot\text{ 4}}{4} \\ k\text{ = 5} \\ \text{ Find y when }x\text{ = 3} \\ y=kx^2 \\ y\text{ = 5 }\cdot(3)^2 \\ y\text{ = 5 }\cdot\text{ 9} \\ y\text{ = 45} \end{gathered}

8 0
1 year ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
oksano4ka [1.4K]

Answer: -1.0018*10^42

Step-by-step explanation:

The Euler Method in numerical analysis is used to approximate the solution to an initial value problem using the tangent line to the solution curve through the (x0,y0) to obtain such approximations.

The euler method equation is:

Yn+1 = Yn + h*f(Xn,Yn)

Where n = number of steps, h = Xn+1 - Xn, f(Xn,Yn) is the slope of the curve at (Xn,Yn).

Variables given in the equation

Y(X=0) = 9,

X0 = 0.

h = step = 0.2

f(X,Y) = X^2*Y - 12*Y^2

B

For the first step, n = 0 in the euler equation. Therefore we have:

Y1 = Y0 + h*f(X0,Y0)

Substituting the Y0 = 9 and X0 = 0 into the function f(X,Y) = X^2*Y - 12*Y^2 = 0^2*9 - 12*9^2 = -972.

Therefore Y1 = 9 + 0.2*(-972) = -185.4.

For n = 1

Repeating the same step with X1 = X0 + h = 0 + 0.2 = 0.2,

Y1 = -185.4,

h = 0.2.

Substitute the variables into the equation Y2 = Y1 + h*f(X1,Y1) and f(X1,Y1) = X1^2*Y1 - 12*Y1^2

Y2 = -82682.4672.

Continue the iterations following the steps above till the result is reached.

The summary of the iteration.

When n = 0, X = 0, Y = -185.4

When n = 1 , X = 0.2, Y = -82682.4672

When n = 2 , X = 0.4, Y = -1.6407*10^10

When n = 3, X = 0.6, Y = -6.4609*10^20

When n = 4, X = 0.8, Y = -1.0018*10^42

4 0
3 years ago
PLEASE HELP I WILL PICK BRAINLIEST
Mnenie [13.5K]

Answer:

A more complex question has rarely been asked.

Principia Mathematica took nearly a thousand pages to prove that 1+1=2. It does meander a bit, but had they wanted to prove 1+1=2 alone, it could have done so in 500 pages.

Mathematically speaking, the definition of 1 is:

There exists a number such that when multiplied upon an element of a specified set, yields the element of the specified set.

It is also defined as:

1.0000000000000000000000…

.9999999999999999999999999…

as the set of all singletons.

a singleton is a set with exactly 1 element.

These 4 definitions work in tandem with one another.

For example:

1=1

Divide both sides by 3.

1/3=1/3

Rewrite.

1/3=.33333333333333333...

Multiply both sides by 3.

1=.9999999999999999999...

Similarly:

If    =.9999999999999999999...

10=9.99999999999999999...

10=9+.99999999999999...

10=9+

Simplify by subtracting x from both sides.

9=9

=1

.99999999999999999999...=1

As the set of all singletons, 1 is also THE element that represents the set of all single entities.

That is to say: if you have 7 erasers. What you really have is a set of 7 single entities. The definition of 7 becomes: 1 + 1 + 1 + 1 + 1 + 1 + 1; and not as is commonly believed as: 6 + 1.

There is an argument for 7 to be defined as 6 + 1, but this argument is a corollary of the Peano Axioms which in turn argues that there exists a set with absolutely nothing in it {} and a set with exactly something in it {x}. More on this later.

The Principia Mathematica uses Peano's (from the Peano Axioms mentioned earlier) work and notation to expertly slice through the many nuances pertaining to this question.

This is something we will not do; but hopefully, we will also be able to effectively demonstrate why 1 + 1 = 2 in less than 1000 pages.

We will assume these basic principles of number theory:

There exists a number such that when multiplied to an element of a specific set, yields that element of the specific set.

There exists a number such that when added to an element of a specific set, yields that element of the specific set.

If we again assume to have only two sets, a set that is empty: {} containing no elements, and a set that is not empty {x} containing an element. We realize that Consequently, we went from nothing {}, to something {x}. This means that {x} is the successor to {}, as the next step up from nothing, is something.

As such we now have two elements:

Nothing, {}, and something that comes after {}, this something is called the successor, and it is the Successor of nothing.

in written notation we have:

{} and { the Successor of nothing }

Rewritten:

{0, the thing that comes after 0}

Further reworded:

{0, Successor (0) }

Reduced further:

0,(0)

Where S(0) stands in place of ‘the successor’. Further, we know there are an infinite number of possible Natural numbers, and we get:

{0, Successor of 0, the successor of the successor of 0, the successor of the successor of the successor of 0,…}

Further reduced:

0,(0),((0)),(((0))),((((0)))),(((((0)))),…

Further explained:

We know that we had nothing, and added something to it, and got something:

Nothing + Something = Successor of nothing.

0+__=(0)

We also know that there is nothing closer to 0, than the thing that comes after 0.

0+(0)=(0)

This implies that S(0) is the smallest increment possible from natural number to next natural number.

As a consequence, we now have two discovered entities: Something, and Nothing.

Let’s give them names.

We have decided that

Nothing = 0 .

0 = Nothing.

S(0) is the something that comes after nothing.

We define a new symbol: 1, to be: 1 = S(0)

This is to say that 1 IS the symbol that succeeds 0;

We could have drawn any shape to define the number that succeeds 0; we chose to draw a 1.

0+(0)=(0)

0+1=(0)

0+1=1

0,1,((0)),(((0))),((((0)))),(((((0)))),…

We now have definitions for 0, and 1. What about a definition for the thing that comes after one? The successor of 1?

As we know S(0) is the smallest increment available, and we are interested in finding S(0)’s successor we investigate:

The successor to the successor of Nothing:

0+(0)=1;1+(0)=(1)

This reads:

The successor of the successor of nothing IS the successor of one

And now… we need a new symbol.

We define the

(1)=2

The successor of 1 IS 2.

Thus:

0+(0)=1;1+(0)=(1)=2

Simplify:

0+1=1;1+1=(1);(1)=2.

Further:

0+1=1;1+1=2;2=2.

1 has many different properties; but all of the properties and their resulting definitions have little to do with why 1 + 1 = 2. And that 1 + 1 = 2 is a byproduct of properties inherent to Natural numbers.

Step-by-step explanation:

6 0
3 years ago
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